The cart's acceleration to the right after the mass is released is determined as 7.54 m/s².
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Acceleration of the cart</h3>
The acceleration of the cart is determined from the net force acting on the mass-cart system.
Upward force = Downward force
ma = mg
13a = 10(9.8)
13a = 98
a = 98/13
a = 7.54 m/s²
Thus, the cart's acceleration to the right after the mass is released is determined as 7.54 m/s².
Learn more about acceleration here: brainly.com/question/14344386
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Answer:
The distance it has traveled is 3,050 m and the magnitude of its displacement is 650 m north.
Explanation:
Distance refers to the length between any two points in space, while displacement refers to the distance from a start position to an end position regardless of the path.
In other words, distance refers to how much space an object travels during its movement; is the quantity moved. It is also said to be the sum of the distances traveled. The distance traveled by a mobile is the length of its trajectory and it is a scalar quantity. In this case, the distance is calculated as:
1850 m + 1200 m= 3,050 m
Displacement refers to the distance and direction of the final position from the initial position of an object. The displacement effected is a vector quantity. The vector representing the displacement has its origin in the initial position, its end in the final position, and its module is the distance in a straight line between the initial and final positions. That is, when expressing the displacement it is done in terms of the magnitude with its respective unit of measurement and the direction because the displacement is a vector type quantity. Mathematically, the displacement (Δd) is calculated as:
Δd= df - di
where df is the final position and di is the initial position of the object.
In this case, the displacement is calculated as:
1850 m - 1200 m= 650 m
Since the distance to the north is greater, the direction of travel will be to the north.
<u><em>The distance it has traveled is 3,050 m and the magnitude of its displacement is 650 m north.</em></u>
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If an object is thrown in an upward direction from the top of a building 1.60 x 102 ft. high at an initial velocity of 21.82 mi/h, what is its final velocity when it hits the ground? (Disregard wind resistance. Round answer to nearest whole number and do not reflect negative direction in your answer.)
this question is troubling me i guessed 96 ft/s
can someone help me out and explain it thanks so much!!!!!!
