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vodka [1.7K]
3 years ago
13

A car is at velocity of 20 km/h. If the car traveled 120 km in 3 hours at constant acceleration, what is its final velocity?

Physics
1 answer:
dedylja [7]3 years ago
8 0
The velocity is dueuueue. 100
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A 35.9 g mass is attached to a horizontal spring with a spring constant of 18.4 N/m and released from rest with an amplitude of
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Answer:

7.74m/s

Explanation:

Mass = 35.9g = 0.0359kg

A = 39.5cm = 0.395m

K = 18.4N/m

At equilibrium position, there's total conservation of energy.

Total energy = kinetic energy + potential energy

Total Energy = K.E + P.E

½KA² = ½mv² + ½kx²

½KA² = ½(mv² + kx²)

KA² = mv² + kx²

Collect like terms

KA² - Kx² = mv²

K(A² - x²) = mv²

V² = k/m (A² - x²)

V = √(K/m (A² - x²) )

note x = ½A

V = √(k/m (A² - (½A)²)

V = √(k/m (A² - A²/4))

Resolve the fraction between A.

V = √(¾. K/m. A² )

V = √(¾ * (18.4/0.0359)*(0.395)²)

V = √(0.75 * 512.53 * 0.156)

V = √(59.966)

V = 7.74m/s

8 0
3 years ago
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Background information about reflection and refraction of light
KIM [24]

Answer:

reflection :

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refraction :

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3 years ago
PLS ANSWER FAST WILL GIVE BRAINLEST!!
egoroff_w [7]

Answer:

from

force =mass x acceleration

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m = f/a

m = 7.5/15

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What is the difference between the two graphs
kupik [55]

Answer:

one of the graph is postion-time graph while the other one is velocity-time graph

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(eopt)s. Find the power dissipated in a 25 r heater<br>connected to a 220V outer.​
Alex Ar [27]

Answer:

P = 1936 W

Explanation:

Given that,

Voltage, V = 220 V

The resistance of the heater, R = 25 ohms

We need to find the power dissipated in the heater. We know that the power dissipated by the electric appliances is given by :

P=\dfrac{V^2}{R}\\\\P=\dfrac{(220)^2}{25}\\\\P=1936\ W

So, the required power is equal to 1936 W.

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