The depth of water in a reservoir increases from 14m to 15.75m. Work out the percentage increase.

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

An angle measures 36° more than the measure of a complementary angle. what is the measure of each angle?

nexus9112 [7]

An acite becaues it lowers than the others

6 0

3 years ago

The ratio of the price of a used washer to a new one is 1:3. If the new washer cost $720 how much could you resell it used?

Alja [10]

$\bf \begin{array}{ccllll}
used&new\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&3\\
u&720
\end{array}\implies \cfrac{1}{u}=\cfrac{3}{720}\implies \cfrac{720\cdot 1}{3}=u$

4 0

3 years ago

Read 2 more answers

The first blanks options are -2 , -1/2 , 2 , 1/2

Pie

Answer:

equation 1

y = -2x

equation 2

y = x-3

Solution to both

(1,-2)

Step-by-step explanation:

We need to get the equations of both lines

General form is;

y = mx + c

where m is slope and c is the y-intercept

Table 1

since we have a point 0,0; the y-intercept here is zero

Let us get the slope. We can do this by selecting any two points

m = (y2-y1)/(x2-x1)

m = (2-10)/(-1+5) = -8/4 = -2

So the equation of the first line is;

y = -2x

Table 2

we get the slope

m = (4+2)/(7-1) = 6/6 = 1

The partial equation is;

y = x + c

To get c, we select any two point and substitute

4 = 7 + c

c = 4-7

c = -3

So the equation is;

y = x-3

To get the solution to both systems, we equate the y

-2x = x - 3

-2x-x = -3

-3x = -3

x = -3/-3

x = 1

To get y, we substitute;

recall; y = -2x

y = -2(1)

y = -2

Solution to the system is;

(1,-2)

7 0

3 years ago

(12) The Earth is one astronomical unit from the

swat32

X+5

Y-7

Fractions can someone help me pls

7 0

3 years ago

Read 2 more answers