Answer:
C
Step-by-step explanation:
Asymptote is basically a line that the graph approaches but NEVER cuts/crosses.
<em><u>Remember, x = a where a is a constant is an equation of a vertical line and x = b, where b is a constant, is the equation of a horizontal line.</u></em>
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- Looking at the graph, we can see that the curve doesn't cross an imaginary line at x = 0, this is a vertical asymptote.
- Also, we can see that the curve doesn't cross an imaginary line at y = -2, this is a horizontal asymptote.
Looking at the answer choices, the choice C is right.
W=12 would be the correct answer. I got this because if you divided 12 by 2, (12/2) you would get 6!
Answer:
domain: x>3/5
Step-by-step explanation:
First we need to derive our function g(x) to get a new function g'(x)
To do this we will have to apply chain rule because we have an inner and outer functions.
Our G(x) = square root(3-5x)
Chain rule formula states that: d/dx(g(f(x)) = g'(f(x))f'(x)
where d/dx(g(f(x)) = g'(x)
g(x) is the outer function which is x^1/2
f(x) is our inner function which is 3-5x
therefore f'(x)= 1/2x^(-1/2) and f'(x) = -5
g'(f(x)) = -1/2(3-5x)^(-1/2)
Applying chain rule then g'(x) = 1/2 (3-5x)^(-/1/2)*(-5)
But the domain is the values of x where the function g'(x) is not defined
In this case it will be 3-5x > 0, because 3-5x is a denominator and anything divide by zero is infinity/undefined
which gives us x >3/5
Answer:
You would have to find the area of the whole rectangle without the spece, so it would be 30mm x 15mm, the result would be 450 square mm.
Then you find the area of the empty space which would be 10mm x 8mm, the result: 80 square mm.
You substract the area of the space from the whole rectangle, which would be 370 square mm, this is the area of the figure
THE ANSWER IS A:
This is the function:
f(x)=|42.67-x|.
42.670 -.002 =42.668
42.668 mm to 42.670
Explanation:
Production will be stopped if the difference in diameter is greater than 0.002 mm.
This difference can mean that the golf ball has a diameter more than 0.002 larger than 42.67 mm, or a diameter more than 0.002 smaller than 42.67. This is the reason for using an absolute value function.
Absolute value represents the distance a number is from 0. For this function, we would want only the values where the function is less than 0.002.
