1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Deffense [45]
3 years ago
11

David is driving on the highway. He begins the trip with 14 gallons of gas in his car. The car uses up one gallon of gas every 2

0 miles. Let G represent the number of gallons of gas he has left in his tank, and let D represent the total distance (in miles) he has traveled. Write an equation relating G to D, and then graph your equation.

Mathematics
1 answer:
ehidna [41]3 years ago
4 0

Answer:

G = -D/20 + 14

Graph in the image attached.

Step-by-step explanation:

Using the model of a linear equation, we have:

G = aD + b

'b' is the y-intercept of the equation, that is, the inicial value of G, when D = 0.

So if David starts the trip with 14 gallons of gas, we have b = 14.

'a' is the slope of the line, that is, an increase of 1 in the value of D causes an increase of 'a' in the value of G.

So if the car uses one gallon every 20 miles, the value of a is -1/20 (an increase of 20 in D causes a decrease of 1 in G).]

So our equation is:

G = -D/20 + 14

The graph of this equation is in the image attached.

You might be interested in
Simplify. Rationalize the denominator. 3/9-√2​
Gwar [14]

\frac{3}{9-\sqrt{2} } * \frac{9+\sqrt{2}}{9+\sqrt{2}}

\frac{27 + 3\sqrt{2} }{9^{2} - (\sqrt{2})^{2}  }

\frac{27 + 3 \sqrt{2} }{81 - 2}

\frac{27 + 3\sqrt{2} }{79}

5 0
3 years ago
Find the area of the shaded region Gh= 13yd
Feliz [49]

Answer:

area ≈ 344. 93 yard²

Step-by-step explanation:

The question you are asking is a circle with shaded portion and a portion not shaded  . The radius of the circle is given as 13 yards . H is the center of the circle and unshaded part of the the sector has an angle of 126°.

The area of a sector = ∅/360 × πr²

The other angle of the shaded  portion is unknown . To find the angle we subtract 126° from 360°(complete angle).

360 - 126 = 234°

area of a sector = ∅/360 × πr²

where

∅ = 234°

r = 13 yards

area =  234/360 × π × 13²

area = 234/360 × π × 169

area = 39546π/360

area = 109.85π

area = 109.85 × 3.14

area  of the shaded part = 344.929  yard²

nearest hundred will be

area ≈ 344. 93 yard²

4 0
3 years ago
Order at the end and help pls ​
Elena L [17]

Answer:

#4- Descending- 9140, 4593, 3401, 1250

#5- Ascending- 1845, 4478, 7324, 9750

3 0
2 years ago
Find the minimum of the data set.
Natalija [7]

Answer:

23,600.

Step-by-step explanation:

23|6

7 0
2 years ago
Hi guys can u also help me with this, i don’t understand a single thing of it
Bess [88]
HCF=Highest Common Factor-HCF of two or more numbers is the greatest factor that divides the numbers. For example, 2 is the HCF of 4 and 6.
LCM=Least Common Multiple-LCM is the smallest positive number that is a multiple of two or more numbers.

Answers:
1) 6
2) 12
3) 5
4) 3
5) 26
6) 15
7) 88
6 0
1 year ago
Other questions:
  • Find the equation of the line shown in the graph. Write the equation in slope-intercept form.
    9·1 answer
  • Factor the following trinomial expression by a method of your choice: 3x2 + 7x-10.
    8·2 answers
  • What do 16 and 24 have in common​
    8·1 answer
  • A gymnasium can hold no more than 650 people. A permanent permanent bleacher in the gymnasium holds 136 people. The event organi
    15·2 answers
  • F(x) = x2 – 7, and g(x) = 5 – x2 then g(f(-4)) =
    11·1 answer
  • If u can do all that will be great tysm
    9·2 answers
  • GOOD AT MATH!! PLEASE HELPPP
    8·1 answer
  • Which rule would you use to test this parallelogram​
    5·2 answers
  • Can someone help me solve this problem for me!!!!!! <br> I need help on this ASAP!!!!!!! Now
    14·1 answer
  • If f = {(4, 2).(5, 1),(6, 2),(7, 3),(8, 6)), then the range of f is
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!