They’re complimentary angles (add up to 90)
Answer:
<em><u>48</u></em>
Step-by-step explanation:
<em><u>3</u></em><em><u>(</u></em><em><u>4</u></em><em><u>)</u></em><em><u>^</u></em><em><u>2</u></em>
<em><u>48</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em>
2149 seats. Since 2149 rounds down to 2100 at the nearest hundred, this is the greatest amount of seats possible in the stadium. If there were 2150 seats, it would round to 2200 seats, so 2149 seats is the correct answer.
Hope this helps!
Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Answer:
ok, I can help. Where's the math problem ?
Step-by-step explanation: