No. Chemical compounds are seldom similar to the elements they're made of.
Here is another example to think about:
<em><u>Sodium</u> . . .</em>
a soft, silvery-white, highly reactive metal;
If exposed to air, the surface rapidly tarnishes and turns dark.
It reacts with water, to the point that a large piece in water may explode.
<em><u>Chlorine</u></em> . . .
a pale yellow-green gas at room temperature;
a strong bleach and disinfectant;
in the upper atmosphere, responsible for ozone depletion;
extremely dangerous and poisonous for all living organisms;
used in World War I as the first chemical warfare agent;
<em><u>Chemical compound of sodium and chlorine</u> . . .
</em>not a highly reactive metal
does not tarnish and turn dark when exposed to air
does not explode in water
not pale yellow-green<em>
</em>not a gas at room temperature
not useful for bleach or disinfectant
not responsible for ozone depletion
not dangerous or poisonous for living organisms
never used as a chemical warfare agent
chemical name: "sodium chloride"
common name: "salt"
widely used in cooking and eating, to season food
How long it takes to revolve around the sun
Question; what causes earthquakes?
Answer; what causes earthquakes are mainly when rocks are underground and then suddenly break along a fault.
Answer:
V(t) = (q0/C) * e^(−t/RC
)
Explanation:
If there were a battery in the circuit with EMF E , the equation for V(t) would be V(t)=E−(RC)(dV(t)/dt) . This differential equation is no longer homogeneous in V(t) (homogeneous means that if you multiply any solution by a constant it is still a solution). However, it can be solved simply by the substitution Vb(t)=V(t)−E . The effect of this substitution is to eliminate the E term and yield an equation for Vb(t) that is identical to the equation you solved for V(t) . If a battery is added, the initial condition is usually that the capacitor has zero charge at time t=0 . The solution under these conditions will look like V(t)=E(1−e−t/(RC)) . This solution implies that the voltage across the capacitor is zero at time t=0 (since the capacitor was uncharged then) and rises asymptotically to E (with the result that current essentially stops flowing through the circuit).
Answer:
To find the weight of something, simply multiply its mass by the value of the local gravitational field, and you get a result in newtons (N). For example, if your mass is 50 kg (about 110 pounds), then your weight is (50) (9.8). The point that must be overwhelmingly emphasized is that weight is a force.
Explanation: