Answer:
The magnitude of the average induced emf in the wire during this time is 9.533 V.
Explanation:
Given that,
Radius r= 0.63 m
Magnetic field B= 0.219 T
Time t= 0.0572 s
We need to calculate the average induce emf in the wire during this time
Using formula of induce emf



.....(I)
In reshaping of wire, circumstance must remain same.
We calculate the length when wire is in two loops



The length when wire is in one loop




We need to calculate the initial area

Put the value into the formula


The final area is



Put the value of initial area and final area in the equation (I)


Negative sign shows the direction of induced emf.
Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.
Answer:
Length, l = 0.866 meters
Explanation:
Given that,
Frequency of sound, f = 99 Hz
Speed of sound in air, v = 343 m/s
To find,
The length of a wind instrument.
Solution,
The standing wave will gets formed in wind instrument. For the closed tube, the closed tube the frequency is given by :

Where
l is the length of the instrument


l = 0.866 meters
So, the length of a wind instrument is 0.866 meters. Hence, this is the required solution.
Na + Cl
An ionic bond is made between a metal and a non-metal
The smaller the area the greater the pressure, while the bigger the smaller the pressure. So they are inversely proportional
Power = work / time = 8000J / 20s = 400W