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o-na [289]
3 years ago
10

PLS ANSWER REALLY EASY! WILL MARK BRAINLIEST.

Physics
1 answer:
lorasvet [3.4K]3 years ago
5 0

Explanation:

They are;

  • The vertical columns of periodic table is called group and the horizontal rows of periodic table is called periods.
  • The valance electron of all elements in the same group are the same but in periods the valance electron of elements in the same period increases from left to righr.
  • The size of atoms increases top to bottom. but in case of periods the size of atoms decreases from left to right.
  • Metalic reactivity increases and non metalic reactivity decreases from top to bottom. but in periods metalic reactivity decreases and non metalic reactivity increases from left to right.

<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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A two-turn circular wire loop of radius 0.63 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.219 T. I
Basile [38]

Answer:

The magnitude of the average induced emf in the wire during this time is 9.533 V.

Explanation:

Given that,

Radius r= 0.63 m

Magnetic field B= 0.219 T

Time t= 0.0572 s

We need to calculate the average induce emf in the wire during this time

Using formula of induce emf

E=-\dfrac{d\phi}{dt}

E=-B\dfrac{dA}{dt}

E=-B\dfrac{A_{2}-A_{1}}{dt}

E=B\dfrac{A_{1}-A_{2}}{dt}.....(I)

In reshaping of wire, circumstance must remain same.

We calculate the length when wire is in two loops

l=2\times 2\pi\times r_{1}

l=2\times 2\pi\times 0.63

l=7.916\ m

The length when wire is in one loop

l=2\pi\times r_{2}

7.916=2\times \pi\times r_{2}

r_{2}=\dfrac{7.916}{2\times \pi}

r_{2}=1.259\ m

We need to calculate the initial area

A_{1}=N\times\pi\times r_{1}^2

Put the value into the formula

A_{1}=2\times3.14\times(0.63)^2

A_{1}=2.49\ m^2

The final area is

A_{2}=N\times\pi\times r_{2}^2

A_{2}=1\times\pi\times(1.259)^2

A_{2}=4.98\ m^2

Put the value of initial area and final area in the equation (I)

E=0.219\dfrac{2.49-4.98}{0.0572}

E=-9.533\ V

Negative sign shows the direction of induced emf.

Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.

6 0
3 years ago
Determine the length of a wind instrument, assuming that it is modeled as a closed tube and that the lowest sound that it can pl
Alex787 [66]

Answer:

Length, l = 0.866 meters

Explanation:

Given that,

Frequency of sound, f = 99 Hz

Speed of sound in air, v = 343 m/s

To find,

The length of a wind instrument.

Solution,

The standing wave will gets formed in wind instrument. For the closed tube, the closed tube the frequency is given by :

f=\dfrac{v}{4l}

Where

l is the length of the instrument

l=\dfrac{v}{4f}

l=\dfrac{343\ m/s}{4\times 99\ Hz}

l = 0.866 meters

So, the length of a wind instrument is 0.866 meters. Hence, this is the required solution.

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Na + Cl

An ionic bond is made between a metal and a non-metal
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How does area affect the pressure?​
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The smaller the area the greater the pressure, while the bigger the smaller the pressure. So they are inversely proportional

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