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1 year ago

Calculate the velocity of an object.

Physics

1 answer:

mylen [45]1 year ago

3 0

Answer:

5.775 m/s

Explanation:

radial acceleration = velocity / radius

=> velocity = radial acceleration * radius

=> v = 3.5 * 1.65 = 5.775 (m/s)

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The current supplied by a battery as a function of time is I(t) = (0.88 A) e^(-t*6 hr). What is the total number of electrons tr

Nimfa-mama [501]

Answer:

$N = 1.2 \times 10^{23}$

Explanation:

As we know that the current through the battery is given as

$i = (0.88 A) e^{-t/6}$

here from above equation we know that current will become zero when time elapsed is very large

so here we can say that charge will flow through the battery from t = 0 to t = infinite

now we have

$q = \int i dt$

$q = \int (0.88 A) e^{-t/6} dt$

$q = 0.88\times -6(3600)\times (e^{-t/6})$

$q = -1.90 \times 10^{4} (0 - 1)$

$q = 1.90 \times 10^{4} C$

As we know that

$q = Ne$

$N = \frac{q}{e}$

$N = \frac{1.90 \times 10^4}{1.6 \times 10^{-19}}$

$N = 1.2 \times 10^{23}$

4 0

2 years ago

Concerning the work done by a conservative force, which of the following statements, if any, are true? It can always be expresse

Vera_Pavlovna [14]

Answer:

It is independent of the path of the body and depends only on the starting and ending points.

Explanation:

In Physics we define a conservative force as a force that is independent of the path of the body and depends only on the starting and ending points.

For conservative forces we can write;

KEi + PEi = KEf +PEf

where;

KEi= initial kinetic energy

PEi= initial potential energy

KEf= final kinetic energy

PEf= final potential energy

This equation is known as the principle conservation of mechanical energy . It applies only to conservative forces where friction is negligible. The term KE + PE is also known as the total mechanical energy of the system.

3 0

3 years ago

Three dogs (Spot, Fido, and Steinberg) are pulling on a chew toy. The chew toy is experiencing no acceleration. Spot is pulling

quester [9]

Answer:

The magnitude and direction of the force applied by Steinberg are approximately 15.192 newtons and 126.704º.

Explanation:

The chew toy is at equilibrium and experimenting three forces from three distinct dogs. The Free Body Diagram depicting the system is attached below. By Newton's Laws we construct the following equations of equilibrium: (Sp is for Spot, F is for Fido and St is for Steinberg) All forces and angles are measured in newtons and sexagesimal degrees, respectively:

$\Sigma F_{x} = F_{F}\cdot \cos \theta_{F} + F_{St,x} = 0$ (1)

$\Sigma F_{y} = F_{F}\cdot \sin \theta_{F}-F_{Sp}+F_{St,y} = 0$ (2)

If we know that $F_{F} = 20\,N$ , $F_{Sp} = 30\,N$ and $\theta_{F} = 63^{\circ}$ , then the components of the force done by Steinberg on the chewing toy is:

$F_{St,x} = -F_{F}\cdot \cos \theta_{F}$

$F_{St,x} = -(20\,N)\cdot \cos 63^{\circ}$

$F_{St, x} = -9.080\,N$

$F_{St,y} = F_{Sp}-F_{F}\cdot \sin \theta_{F}$

$F_{St,y} = 30\,N-(20\,N)\cdot \sin 63^{\circ}$

$F_{St, y} = 12.180\,N$

The magnitud of the force is determined by Pythagorean Theorem:

$F_{St} = \sqrt{F_{St,x}^{2}+F_{St,y}^{2}}$

$F_{St} =\sqrt{(-9.080\,N)^{2}+(12.180\,N)^{2}}$

$F_{St} \approx 15.192\,N$

Since the direction of this force is in the 3rd Quadrant on Cartesian plane, we determine the direction of the force with respect to the eastern semiaxis:

$\theta_{St} = 180^{\circ} + \tan^{-1} \left(\frac{F_{St,y}}{F_{St,x}}\right)$