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1 year ago

How do i calculate the kinetic energy

Physics

1 answer:

Stella [2.4K]1 year ago

4 0

The kinetic energy is found at 150 J. The work-energy theorem is applied in the given equation.

<h3>What is Kinetic energy?</h3>

The energy possessed by the body by the virtue of motion is known as Kinetic energy. It is found as the product of mass and the square of the velocity.

The given data in the problem is;

The mass is, m=0.15 kg

Force, F=300 N

Distance,d=0.50 m

From the work-energy theorem, kinetic energy is equal to the work done.

Work done = Kinetic energy

$\rm F \times d = KE \\\\ KE= 300 \times 0.50 \\\\ KE=150 \ J$

Hence, kinetic energy is found at 150 J.

To learn more about the kinetic energy, refer to the link;

brainly.com/question/12669551

#SPJ1

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3 years ago

A particle moves in a straight line with the velocity function v ( t ) = sin ( w t ) cos 3 ( w t ) . find its position function

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Integrating the velocity equation, we will see that the position equation is:

$$f(t)=\frac{\cos ^3(\omega t)-1}{3}$

<h3>How to get the position equation of the particle?</h3>

Let the velocity of the particle is:

$$v(t)=\sin (\omega t) * \cos ^2(\omega t)$

To get the position equation we just need to integrate the above equation:

$$f(t)=\int \sin (\omega t) * \cos ^2(\omega t) d t$

$$\mathrm{u}=\cos (\omega \mathrm{t})$

Then:

$$d u=-\sin (\omega t) d t$

$\Rightarrow d t=-d u / \sin (\omega t)$

Replacing that in our integral we get:

$\int \sin (\omega t) * \cos ^2(\omega t) d t$

$-\int \frac{\sin (\omega t) * u^2 d u}{\sin (\omega t)}-\int u^2 d t=-\frac{u^3}{3}+c$

Where C is a constant of integration.

Now we remember that $u=\cos (\omega t)$

Then we have:

$$f(t)=\frac{\cos ^3(\omega t)}{3}+C$

To find the value of C, we use the fact that f(0) = 0.

$$f(t)=\frac{\cos ^3(\omega * 0)}{3}+C=\frac{1}{3}+C=0$

C = -1 / 3

Then the position function is:

$$f(t)=\frac{\cos ^3(\omega t)-1}{3}$

Integrating the velocity equation, we will see that the position equation is:

$$f(t)=\frac{\cos ^3(\omega t)-1}{3}$

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1 year ago

A sled starts off with an initial velocity of 8 m/s and slows down to 2 m/s after 3 seconds. What was its acceleration?

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Answer:

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Explanation:

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2 years ago

A disk-shaped grindstone of mass 3.0 kg and radius 8.0 cm is spinning at 600 rev/min. After the power is shut off, a man continu

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Answer:

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Explanation:

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$\alpha=6.283rad/s^2$

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$\tau=I*\alpha$

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3 years ago