A tow truck exerts a net horizontal force of 1050 n on a 760-kg car. what is the acceleration of the car during this time?

2 answers:

6 0

A = f/m

a= 1050/760

a= 1.38m/s^2

dlinn [17]4 years ago

4 0

Answer: The acceleration of the car during this time is 1.38 $m/s^2$ .

Explanation:

Force exerted on the two truck = 1050 N

Mass of the car = 760 kg

According to Newton's second law of Motion;

$Force=Mass \times Acceleration$

$1050 N=760 kg\times Acceleration$

$Acceleration=\frac{1050 N}{760 kg}=1.38 m/s^2$

The acceleration of the car during this time is 1.38 $m/s^2$ .

You might be interested in

denis23 [38]

When a mycelium infiltrates an unexploited source of dead organic matter fungal enzymes are most likely to appear within the food source.

<h3>What is a mycelium?</h3>

A network of hyphae or fungal threads is known as mycelium.
Mycelia often grow underground but can also thrive in other places such as rotting tree trunks.
A mycelium can be developed by a single spore. The fruiting bodies of fungi, such as mushrooms are sprouted from a mycelium.
Mycelia are of crucial importance to the soil. Organic materials are broken by them making the raw materials available again for use in the ecosystem.
Almost 92% of plant families interact with fungi. This type of symbiosis is termed mycorrhiza.
Hyphae are an important source of food for insects and other invertebrates.