Question

A tow truck exerts a net horizontal force of 1050 n on a 760-kg car. what is the acceleration of the car during this time?

Answer 1

A = f/m

a= 1050/760

a= 1.38m/s^2

Answer 2

Answer: The acceleration of the car during this time is 1.38 $m/s^2$.

Explanation:

Force exerted on the two truck = 1050 N

Mass of the car = 760 kg

According to Newton's second law of Motion;

$Force=Mass \times Acceleration$

$1050 N=760 kg\times Acceleration$

$Acceleration=\frac{1050 N}{760 kg}=1.38 m/s^2$

The acceleration of the car during this time is 1.38 $m/s^2$.