All categories

3 years ago

What is 8/3 plus 3/7

Mathematics

2 answers:

miskamm [114]3 years ago

3 0

I believe that would equal 65/21

hope that helps!

ANEK [815]3 years ago

3 0

8/3 + 3/7
First find least common denominators . The LCD is 21...
So 56/21 + 9/21
Which is 65/21
Then simplify it to a mixed number..
3 2/21 is your answer.

You might be interested in

Find a coterminous angle between 0 and 2 pi for each given angle. 191pi/45

Sedaia [141]

Check the picture below.

let's recall that 2π is a full go-around or namely a revolution

$\bf \cfrac{191}{45}\implies \cfrac{45+45+45+45+11}{45}\implies \cfrac{45}{45}+\cfrac{45}{45}+\cfrac{45}{45}+\cfrac{45}{45}+\cfrac{11}{45} \\\\\\ 1+1+1+1+\cfrac{11}{45}\implies \stackrel{\textit{and this more}}{\underset{\textit{2 go-around}}{\underset{\uparrow }{2+2}+\stackrel{\downarrow }{\cfrac{11}{45}}}}$

5 0

3 years ago

PLEASE HELP ASAP

Vilka [71]

Answer:

A, 152 cm.

Step-by-step explanation:

A rectangular pyramid has a volume equation of

V = (lwh)/3.

Therefore, when we plug the values in:

[(7)(5)(13)]/3 = V

V = 455/3

V = 151.666667

V is approximately equal to 152 cm^3.

I hope this helped! :)

5 0

2 years ago

Please answer the following Question (35 Points)

True [87]

Answer:

Step-by-step explanation:

7 0

2 years ago

Rob coloured 1/4 of a rectangle .what is another way to name 1/4?

mixas84 [53]

another way to name 1/4 is a quarter because 1/4 of 100 is 25 %, so that's why it is called a quarter.

hopefully this helps you :)

5 0

3 years ago

Find the zeros (roots) of the following equations. f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0

Talja [164]

Hi,
$f(1)=2*1^5-9*1^4+12*1^3-12*1^2+10*1-3\\
=2-9+12-12+10-3\\
=0\\

f(x)=(x-1)(2x^4-7x^3+5x^2-7x+3)\\


g(x)=2x^4-7x^3+5x^2-7x+3\\

g(3)=2*3^4-7*3^3+5*3^2-7*3+3\\
=162-189+45-21+3\\
=0\\

g(x)=(x-3)(2x^3-x^2+2x-1)\\

h(x)=2x^3-x^2+2x-1\\

h( \dfrac{1}{2} )=2* \dfrac{1}{8} - \dfrac{1} {4}+1-1\\
=0\\

h(x)=(2x-1)(x^2+1)\\


f(x)=(x-1)(x-3)(2x-1)(x+i)(x-i)\\


$
Roots are 1,3,0.5,i,-i.

8 0

3 years ago