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3 years ago

Sin(-120) in exact value

Mathematics

1 answer:

cupoosta [38]3 years ago

3 0

Step-by-step explanation:

$\because \: sin \: ( - \theta) = - sin \: \theta \\ \\ \therefore \: sin \: ( - 120 \degree) = - sin \: 120 \degree \\ \\ = - sin \: ( 180\degree- 60 \degree) \\ \\ = - sin \: 60 \degree \\ \\ = - \frac{ \sqrt{3} }{2} \\ \\ \purple{ \boxed{\therefore \: sin \: ( - 120 \degree) =- \frac{ \sqrt{3} }{2} }}$

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Hep I’m bout to fail if I don’t get this right will give brainless if correct

nalin [4]

Answer:

$x = 4$

$ac = 56$

Step-by-step explanation:

$6x + 3 = 7x - 1$

$7x - 6x = 3+ 1$

$6x + 3 + 7x + 1 = 56$

$x = 4$

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3 years ago

when a probability is expressed as a fraction, what does the bottom number represents A. the number of possible out comes B. the

masya89 [10]

Answer:

A. the number of possible out comes

Step-by-step explanation:

Probability is the chance of an event/something to happen.

The formula is;

Probability = the number of ways of achieving success/Total number of outcomes

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3 years ago

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leva [86]

Answer:

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Step-by-step explanation:

4 0

3 years ago

Segment PE has endpoints P(-4,4) and E(0,-4). Find the coordinates of point Q such that PQ:QE is 1:3. Enter the coordinates belo

Natalka [10]

Answer:

(-3, 2)

Step-by-step explanation:

Given that point Q, partitions segment PE, such that PQ:QE is 1:3, coordinates of point Q is found using the formula below:

$x = \frac{mx_2 + nx_1}{m + n}$

$y = \frac{my_2 + ny_1}{m + n}$

Where,

$P(-4, 4) = (x_1, y_1)$

$E(0, -4) = (x_2, y_2)$

$m = 1, n = 3$

Plug in the necessary values to find x and y coordinates for point Q as follows:

$x = \frac{mx_2 + nx_1}{m + n}$

$x = \frac{1(0) + 3(-4)}{1 + 3}$

$x = \frac{0 - 12}{4}$

$x = \frac{-12}{4}$

$x = -3$

$y = \frac{my_2 + ny_1}{m + n}$

$y = \frac{1(-4) + 3(4)}{1 + 3}$

$y = \frac{-4 + 12}{4}$

$y = \frac{8}{4}$

$y = 2$

The coordinates of the point Q are (-3, 2))

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3 years ago

Factor the expression -45x^2 +5

klemol [59]

$-45x^2 +5 \\ \\ GCF = 5 \\ \\ 5( \frac{45x^2}{5} - \frac{5}{5} ) \\ \\ -5(9x^2-1) \\ \\ -5((3x)^2-1^2) \\ \\ -5(3x+1)(3x-1) \\ \\ Answer: \fbox {-5(3x+1)(3x-1)}$

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3 years ago