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Snezhnost [94]
3 years ago
15

In which terrestrial biome would you expect to rake leaves? Question 5 options: taiga (coniferous forest) savanna temperate deci

duous forest tundra
Chemistry
2 answers:
seropon [69]3 years ago
3 0

The correct answer is temperate deciduous forest.

Temperate deciduous forests are situated in the mid-latitudes, in between Polar Regions and tropics having average annual temperature about 10°C, rainfall between 750 to 1500 mm. There are four distinct seasons and the vegetation includes mostly broad leaved trees such as maple, beech, oak,  hickory and chestnut.  Leaves fall in winter after changing color in autumn. Leaves grow back in spring. This is an adaption to avoid to live in cold winters.

Simora [160]3 years ago
3 0

The correct answer is C. Temperate deciduous forest

Explanation:

The temperate deciduous forest is a biome found in North America and certain areas of Europe and Asia. This biome as all forest is dominated by trees; additionally, the temperate deciduous forest is different from other ecosystems because this goes through the four seasons every year. This implies the leaves of trees change their color, later they fall and they are renewed. According to this, the temperate deciduous forest is the biome in which you would expect to rake leaves because it is in this biome the leaves of trees fall every year.

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What is the partial pressure (in atm) of CO₂ at 468.2 K in a 25.0 L fuel combustion vessel if it contains 60.0 grams CO₂, 82.1 g
NeTakaya

Answer:

2.09 atm

Explanation:

Step 1: Given and required data

  • Mass of CO₂ (m): 60.0 g
  • Volume of the vessel (V): 25.0 L
  • Temperature (T): 468.2 K

We won't need the data of water and uncombusted fuel, since the partial pressures are independent of each other.

Step 2: Calculate the number of moles (n) corresponding to 60.0 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

60.0 g × 1 mol/44.01 g = 1.36 mol

Step 3: Calculate the partial pressure of CO₂

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T/ V

P = 1.36 mol × (0.0821 atm.L/mol.K) × 468.2 K/ 25.0 L = 2.09 atm

5 0
3 years ago
Sulfuric acid (H2SO4) has a molar mass of 98.1 g/mol. How many oxygen atoms are found in 75.0 g of H2SO4? A. 1.15 × 10^23 B. 1.8
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Answer:

B

Explanation:

first find the no. Of moles of H2SO4

=  75/98.1

= 0.7645

Next step

In on mole of H2SO4 the no.of oxygen atom is 4.

1 H2SO4 : 4 O

0.7645  : x                     x= 0.7645x4= 3.0581

next multiply avogadros constant

3.0581 x 6.022× 10^23 =1.84x10^24

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It determine Gibbs free energy
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