Atomic particles Because the usually have a chain reaction when blown up
Answer:
2.09 atm
Explanation:
Step 1: Given and required data
- Volume of the vessel (V): 25.0 L
We won't need the data of water and uncombusted fuel, since the partial pressures are independent of each other.
Step 2: Calculate the number of moles (n) corresponding to 60.0 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
60.0 g × 1 mol/44.01 g = 1.36 mol
Step 3: Calculate the partial pressure of CO₂
We will use the ideal gas equation.
P × V = n × R × T
P = n × R × T/ V
P = 1.36 mol × (0.0821 atm.L/mol.K) × 468.2 K/ 25.0 L = 2.09 atm
Answer:
B
Explanation:
first find the no. Of moles of H2SO4
= 75/98.1
= 0.7645
Next step
In on mole of H2SO4 the no.of oxygen atom is 4.
1 H2SO4 : 4 O
0.7645 : x x= 0.7645x4= 3.0581
next multiply avogadros constant
3.0581 x 6.022× 10^23 =1.84x10^24
Answer:
Honey but Cheerios pls follow
It determine Gibbs free energy