Answer:
The molecular formula of the compound is
. The molecular formula is obtained by the following expression shown below
![\textrm{Molecular formula }= n\times \textrm{Empirical formula}](https://tex.z-dn.net/?f=%5Ctextrm%7BMolecular%20formula%20%7D%3D%20n%5Ctimes%20%5Ctextrm%7BEmpirical%20formula%7D)
Explanation:
Given molecular mass of the compound is 176 g/mol
Given empirical formula is
Atomic mass of carbon, hydrogen and oxygen are 12 u , 1 u and 16 u respectively.
Empirical formula mass of the compound = ![\left ( 2\times12+4+16 \right ) \textrm{ u} = 44 \textrm{ g/mol}](https://tex.z-dn.net/?f=%5Cleft%20%28%202%5Ctimes12%2B4%2B16%20%5Cright%20%29%20%5Ctextrm%7B%20u%7D%20%3D%2044%20%5Ctextrm%7B%20g%2Fmol%7D)
![n = \displaystyle \frac{\textrm{Molecular formula mass}}{\textrm{Empirical formula mass}} \\n = \displaystyle \frac{176}{44} = 4](https://tex.z-dn.net/?f=n%20%3D%20%5Cdisplaystyle%20%5Cfrac%7B%5Ctextrm%7BMolecular%20formula%20mass%7D%7D%7B%5Ctextrm%7BEmpirical%20formula%20mass%7D%7D%20%5C%5Cn%20%3D%20%5Cdisplaystyle%20%5Cfrac%7B176%7D%7B44%7D%20%3D%204)
![\textrm{Molecular formula }= n\times \textrm{Empirical formula}](https://tex.z-dn.net/?f=%5Ctextrm%7BMolecular%20formula%20%7D%3D%20n%5Ctimes%20%5Ctextrm%7BEmpirical%20formula%7D)
Molecular formula = 4
Molecular formula is ![C_{8}H_{16}O_{4}](https://tex.z-dn.net/?f=C_%7B8%7DH_%7B16%7DO_%7B4%7D)
1. She would want a balanced force so she doesn't fall but, well, keep her balance.
2. Frictional force because when an object slows down it's because a higher amount of friction is acting on it.
3. It would be magnitude and direction because is like the size of the object and they need to know how much force it will take to move it.
4. Is the same as 3...
5. A push and a pull are a force.
I hope this helps!
Lewis Structure:
H -- O -- H (bent, Oxygen has 2 lone pairs)
Percent Composition
Hydrogen percent composition = [ 2 * (Hydrogen mass) ] / [Total mass of H2O]
Oxygen percent composition = [Oxygen mass] / [Total mass of H2O]
dose this make any sense...??
You must add 45 mL of the 80 % alcohol to the 30 % alcohol to get a 35 % solution.
You can use a modified dilution formula to calculate the volume of 80 % alcohol
V1×C1 + V2×C2 = V3×C3
Let the volume of 80 % mixture 1 = <em>x</em> mL. Then the volume of the final 35 % mixture 3 = (405 + <em>x</em> ) mL
(<em>x</em> mL×80 % alc) + (405 mL×30 % alc) = (405 + <em>x</em>)mL × 35 % alc
80x + 12 150 = 14 175 + 35 x
45x = 2025
x = 2025/45 = 45