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MissTica
3 years ago
5

What is the total number of grams of potassium fluoride

Chemistry
1 answer:
Mice21 [21]3 years ago
8 0

Explanation:

molarity=no. of moles of solute/solution in litres

6.17M=no. of moles of solute/9.4 L

6.17×9.4=no. of moles of solute

57.9 =no. of moles of potassium fluoride KF

no. of moles=given mass /molar mass

57.9=given mass/58

3358.2 g

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The solid compound, K2SO4, contains?
givi [52]
The solid compound, K2SO4 contains a cation called K+ and an anion called SO42-. In this case, there are 2 atoms of potassium, 1 atom of sulfur and 4 moles of oxygen. The compound also contains ionic bonds because of the composing non-metals and metal. 
3 0
3 years ago
Which of the following elements does not form a diatomic molecule?
gladu [14]

Answer:

C

Explanation:

Neon is a noble gas, which is monoatomic.

6 0
3 years ago
Solar, wind, and water power are renewable resources and can replace our dependence on fossil fuels. They each have their own dr
Vesna [10]
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8 0
3 years ago
Fill in the coefficients that will balance the following reaction: a0Ca + a1CO2 + a2O2 → a3CaCO3
VashaNatasha [74]
The chemical equation without coefficients is:


Ca + CO2 + O2 --------> Ca CO3


You can balance that equation by trial an error.


This is the chemical equation balanced:


2Ca + 2CO2 + O2 --------> 2Ca CO3


Count the atoms on each side to check the balance


Atom    Left side         right side

Ca         2                     2 

C           2                     2

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Then those are the coefficients:

a0 = 2

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6 0
3 years ago
Which of the followings is true about G0'? A. G0' can be determined using Keq' B. G0' indicates if a reaction can occur under no
nekit [7.7K]

Answer:

A and D are true , while B and F statements are false.

Explanation:

A) True.  Since the standard gibbs free energy is

ΔG = ΔG⁰ + RT*ln Q

where Q= [P1]ᵃ.../([R1]ᵇ...) , representing the ratio of the product of concentration of chemical reaction products P and the product of concentration of chemical reaction reactants R

when the system reaches equilibrium ΔG=0 and Q=Keq

0 = ΔG⁰ + RT*ln Q → ΔG⁰ = (-RT*ln Keq)

therefore the first equation also can be expressed as

ΔG = RT*ln (Q/Keq)

thus the standard gibbs free energy can be determined using Keq

B) False. ΔG⁰ represents the change of free energy under standard conditions . Nevertheless , it will give us a clue about the ΔG around the standard conditions .For example if ΔG⁰>>0 then is likely that ΔG>0 ( from the first equation) if the temperature or concentration changes are not very distant from the standard conditions

C) False. From the equation presented

ΔG⁰ = (-RT*ln Keq)

ΔG⁰>0 if Keq<1 and ΔG⁰<0 if Keq>1

for example, for a reversible reaction  ΔG⁰ will be <0 for forward or reverse reaction and the ΔG⁰ will be >0 for the other one ( reverse or forward reaction)

D) True. Standard conditions refer to

T= 298 K

pH= 7

P= 1 atm

C= 1 M for all reactants

Water = 55.6 M

5 0
3 years ago
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