BEFORE the shot, the cannon is just sitting there with the ball inside.
Their combined momentum is zero.
Momentum is conserved, so their combined momentum has to be
zero AFTER the shot too.
Whatever momentum the ball has in one direction, the cannon
must have the same momentum in the other direction.
Momentum = (mass) x (speed)
Momentum of the ball = (6 kg) x (200 m/s) = 1,200 kg-m/s
Momentum of the cannon =
(2,000 kg) x (speed) = 1,200 kg-m/s
Divide each side by (2,000 kg)
speed = (1,200 kg-m/s) / (2,000 kg)
= 0.6 m/s
That's where the recoil of any gun comes from. The same
momentum as the bullet has, but in the opposite direction.
Answer:
A sample of 5.2 mg decays to .65 mg or to 1/8 of its original amount.
1/8 = 1/2 * 1/2 * 1/2 or 3 half-lives.
3 * 30.07 = 90 yrs for 5.2 mg to decay to .65 mg
You can get these other numbers similarly:
5.2 / .0102 = 510 requires about 9 half-lives which is 30 * 9 = 270 yrs
Answer:F=40.09 N
Explanation:
Given
weight of crate 
Inclination 
Frictional Force 
as the crate is moving with constant velocity therefore net Force on crate is zero
Answer:
the diver's speed is independent of the launch height.
Explanation:
For this exercise we must use Newton's second law
fr - W = m a
the friction force has the general form
fr = b v
Let's analyze this equation to find out what happens with the speed of the distant club.
When jumping, the initial speed is zero, so the friction force is zero and has an acceleration equal to the acceleration of gravity, as the speed increases the friction force increases decreasing the acceleration until it becomes zero, when it arrives at this value the velocity it has is called terminal velocity and this velocity remains fixed in relation to the trajectory.
fr = W
v = cte
The distance or time in which this equilibrium is reached is relatively fast, so the diver's speed is independent of the launch height.
