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devlian [24]
3 years ago
10

A 1000-turn solenoid is 50 cm long and has a radius of 2.0 cm. It carries a current of 18.0 A. What is the magnetic field inside

the solenoid near its center
Physics
1 answer:
vitfil [10]3 years ago
3 0

Answer:

The value  is  B =  0.0452 \  T

Explanation:

From the question we are told that

   The number of turns is  N  =  1000

    The length is  L =  50 cm =  0.50 m  

    The radius is  r =  2.0 cm  =  0.02 m

     The current is I  =  18.0 A

   

Generally the magnetic field is mathematically represented as

         B = \mu_o  * \frac{N }{L}  *  I

Here \mu_o is the permeability of free space with value  

     \mu_o  =  4\pi * 10^{-7} N/A^2

So

     B =  4\pi * 10^{-7}  *   \frac{1000}{0.50} *  18.0

=>   B =  0.0452 \  T

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The kinetic energy of a body is the energy possessed by the body due to its motion. Mathematically,

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The answer to your question is given below.

Explanation:

Mechanical advantage (MA) = Load (L)/Effort (E)

MA = L/E

Velocity ratio (VR) = Distance moved by load (l) / Distance moved by effort (e)

VR = l/e

Efficiency = work done by machine (Wd) /work put into the machine (Wp) x 100

Efficiency = Wd/Wp x100

Recall:

Work = Force x distance

Therefore,

Work done by machine (wd) = load (L) x distance (l)

Wd = L x l

Work put into the machine (Wp) = effort (E) x distance (e)

Wp = E x e

Note: the load and effort are measured in Newton (N), while the distance is measured in metre (m)

Efficiency = Wd/Wp x100

Efficiency = (L x l) / (E x e) x 100

Rearrange

Efficiency = L/E ÷ l/e x 100

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Efficiency = L/E ÷ l/e x 100

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