Question

A 1000-turn solenoid is 50 cm long and has a radius of 2.0 cm. It carries a current of 18.0 A. What is the magnetic field inside the solenoid near its center

Answer 1

Answer:

The value  is  $B = 0.0452 \ T$

Explanation:

From the question we are told that

   The number of turns is  N  =  1000

    The length is  L =  50 cm =  0.50 m  

    The radius is  r =  2.0 cm  =  0.02 m

     The current is I  =  18.0 A

   

Generally the magnetic field is mathematically represented as

         $B = \mu_o * \frac{N }{L} * I$

Here $\mu_o$ is the permeability of free space with value  

     $\mu_o = 4\pi * 10^{-7} N/A^2$

So

     $B = 4\pi * 10^{-7} * \frac{1000}{0.50} * 18.0$

=>   $B = 0.0452 \ T$