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rosijanka [135]
3 years ago
6

An hydrogen molecule consists of two hydrogen atoms whose total mass is 3.3×10−27 kg and whose moment of inertia about an axis p

erpendicular to the line joining the two atoms, midway between them, is 4.0×10−48 kg⋅m2 . Part A From these data, estimate the effective distance between the atoms.
Physics
1 answer:
dlinn [17]3 years ago
3 0

Answer:

6.9631\times 10^{-11}\ m

Explanation:

I = Moment of inertia = 4\times 10^{-48}\ kg m^2

m = Mass of two atoms = 2m = 3.3\times 10^{-27}\ kg

r  = distance between axis and rotation mass

Moment of inertia of the system is given by

I=mr^2\\\Rightarrow I=2mr^2\\\Rightarrow 4\times 10^{-48}=3.3\times 10^{-27}\times r^2\\\Rightarrow r=\sqrt{\frac{4\times 10^{-48}}{3.3\times 10^{-27}}}\\\Rightarrow r=3.48155\times 10^{-11}\ m

The distance between the atoms will be two times the distance between axis and rotation mass.

d=2r\\\Rightarrow d=2\times 3.48155\times 10^{-11}\\\Rightarrow d=6.9631\times 10^{-11}\ m

Therefore, the distance between the two atoms is 6.9631\times 10^{-11}\ m

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Answer:

Distance = velocity x time, so 10 m/s X 10 s = 100 m

Explanation:

If you accelerate at 2 m/s^2 for 10 seconds, at the end of the 10 seconds you are moving at a rate of 20 m/s.

V(f) = V(i) + a*t

Final velocity = initial velocity + acceleration x time

Your average velocity will be half of your final, because you accelerated at a constant rate. So your average velocity is 10 m/s.

Distance = velocity x time, so 10 m/s X 10 s = 100 m

8 0
3 years ago
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A 1170-kg car is held in place by a light cable on a very smooth (frictionless) ramp, as shown in the figure (Figure 1) . The ca
liq [111]
Refer to the diagram shown below.

The mass of the car is 1170 kg, therefore its weight is
W = (1170 kg)*(9.8 m/s²) = 11466 N

The component of the weight acting down the incline is
F = W sin(25°) = (11466 N)*sin(25°) = 4845.7 N

The normal reaction from the inclined plane is
N = W cos(25°) = (11466 N) cos(25°) = 1039.2 N

T =  tension in the cable, acting at 31° above the surface of the ramp.

The Free Body Diagram on the right shows all the forces (friction is ignored)
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NARA [144]

Answer:

5.01×10⁴ J.

Explanation:

Applying,

q = Cm....................... Equation 1

Where q = amount of heat needed to melt the ice, m = mass of the ice, C = specific latent heat of ice.

From the question,

Given: m = 150 g = (150/1000) kg = 0.15 kg, C = 3.34×10⁵ J/kg

Substitute these values into equation 1

q = (0.15×3.34×10⁵)

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3 years ago
A car is traveling at 40 m/s for 20 seconds. How far did it travel in this time?
barxatty [35]
<h3>Answer:</h3>

800 meters

<h3>Explanation;</h3>

<u>We are given;</u>

  • Speed as 40 m/s
  • Time as 20 seconds

We are required to determine the distance traveled

  • Speed refers to the rate of change in distance.
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Speed = Distance ÷ time

Rearranging the formula;

Distance = speed × time

In this case;

Distance = 40 m/s × 20 sec

              = 800 meters

Thus, the distance traveled by the car is 800 m

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7 0
3 years ago
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