<h3><u>Unders</u><u>tanding</u><u> </u><u>the</u><u> </u><u>conc</u><u>ept</u><u>:</u><u>-</u></h3>
Here the concept of Molarity used .We will put the formula of Molarity then we find moles of copper sulphate .Then we can find the.Given weight of Copper sulphate.So let's do
<h3>
Solution:-</h3>
- Volume of Solvent=0.8L
- Molarity=0.6M
We know
Now
Molar Mass of Solute:-
Now
There are 145 centimeters in 1.45 meters.
45.6 mL of 0.0600 M of 
is added to 25.0 mL of HCl of unknown concentration then , the concentration of HCl is 0.032 M .
Calculation ,
Formula used : 
= 
...( 1 )
Where 
= concentration of = 0.0600 M ( given )
= concentration of HCl = ? ( to be find )
= volume of = 25.0 mL ( given )
= volume of HCl = 45.6 mL ( given )
Now , put the value of all volume and concentration in equation ( 1 ) we get .
0.0600 M × 25.0 mL = × 45.6 mL
= 0.0600 M × 25.0 mL / 45.6 mL = 0.032 M
Therefore , concentration of unknown concentration of HCl is 0.032 M .
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Balance Chemical Equation of this reaction is,
2 CO + O₂ → 2CO₂
Acc. to this reaction,
88 g (2 mole) of CO₂ was produced when = 56 g (2 mole)of CO was reacted
So,
24.7 g of CO₂ will be produced by reacting = X g of CO
Solving for X,
X = (56 g × 24.7 g) ÷ 88 g
X = 2.26 g ÷ 88 g
X = 0.0257 g of CO
Result:
0.0257 g of CO is required to be reacted with excess of O₂ to produce 24.7 g of CO₂.
Thermal energy is added to the water
