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astra-53 [7]
3 years ago
6

How was Bohr’s atomic model different from Rutherford’s atomic model?

Chemistry
2 answers:
Savatey [412]3 years ago
4 0

C as i stated before.

Aleks04 [339]3 years ago
3 0

C is the answer.

It says on the third picture that Bohr refined Rutherford's model by giving distinct orbits for the electrons with distinct radii.


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Convert 5.28 x 1019 molecules of C6H1206 to grams.
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Answer:

m=0.0158g

Explanation:

Hello there!

In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.

In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:

m=5.28x10^{19}molecules*\frac{1mol}{6.022x10^{23}molecules}*\frac{180.16g}{1mol}\\\\m=0.0158g

Best regards!

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