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ira [324]
3 years ago
12

The reduction of nitrogen monoxide is described by the following chemical equation: 2H2 (g) +2NO (g) 2H20 ()N2 (g Suppose a two-

step mechanism is proposed for this reaction, beginning with this elementary reaction: H2 g+2NO(g)- N20 (g)+H20(g) Suppose also that the second step of the mechanism should be bimolecular Suggest a reasonable second step. That is, write the balanced chemical equation of a bimolecular elementary reaction that would complete the proposed mechanism
Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

Reasonable Second step- N_{2}O(g)+H_{2}(g)\rightarrow N_{2}(g)+H_{2}O(g)

Explanation:

The given single step chemical reaction is as follows.

2H_{2}(g)+2NO \rightarrow 2H_{2}O(g)+N_{2}(g)

Suppose a two-step mechanism is proposed for this reaction,

The reaction occured in two steps they are as follows.

Step -1:H_{2}(g)+2NO \rightarrow N_{2}O(g)+H_{2}O(g)

Step-2:N_{2}O(g)+H_{2}(g)\rightarrow N_{2}(g)+H_{2}O(g)

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Luba_88 [7]
I think the correct answer is the second option. The statement pertaining to the properties of the element vanadium is reliable because the facts presented are testable or can be verified by doing experimentation. Also, nowadays, many studies are present that contains properties of almost anything.
7 0
3 years ago
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marin [14]

Answer:

A

D

E

and maybe C I'm not sure on that one.

Explanation:

8 0
3 years ago
A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at
lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is  -5485.7 kJ/mol

Explanation:

<u>Step 1:</u> Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

<u> Step 2:</u> Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

<u>Step 3:</u> Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25  = 8.2 °C

q = 1200 * 4.184 * 8.2 =  41170.56 J

<u>Step 4</u>: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J  = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

<u>Step 5</u>: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

<u>Step 6:</u> Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is  -5485.7 kJ/mol

8 0
3 years ago
What is the molarity if a solution that contains 289 grams of sugar in a 2 liter solution?? Molar mass of source is 342.2965g/mo
Olegator [25]

<u>Answer;</u>

= 0.422 M

<h3><u>Explanation;</u></h3>

Molarity or concentration is the number of moles of a solute in 1 liter of a solution.

Therefore; Molarity = n/V ; where n is the number of moles and V is the volume of the solution in L.

Number of moles = Mass/molar mass

                             = 289 g/342.2965g/mol

                             = 0.844 Moles

Therefore;

Molarity = 0.844 moles/ 2L

              = 0.422 M

8 0
4 years ago
A student added magnesium hydroxide to a solution of hydrochloric acid. What is the
r-ruslan [8.4K]

Answer:

bleh

Explanation:

Neutralization reaction between magnesium hydroxide and hydrochloric acid Mg(OH)2(s) + 2HCl(aq) → 2H2O(l) + MgCl2(aq) b.

so uh pretty sure Mg(OH)2(s) + 2HCl(aq) → 2H2O(l) + MgCl2(aq) b.

correct me if im wrong <3

6 0
3 years ago
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