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3 years ago

2 points

Chemistry

1 answer:

quester [9]3 years ago

6 0

(b) 12.7 L

<u>Explanation:</u>

Given:

Volume, V₁ = 12 L

Pressure, P₁ = 760 mm Hg (at STP)

Temperature, T₁ = 273 K (at STP)

Pressure, P₂ = 720 mm Hg

Temperature, T₂ = 0°C = 273 K

Volume, V₂ = ?

We know:

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

Substituting the value we get:

$\frac{760 X 12}{273} = \frac{720 X V_2}{273} \\\\V_2 = \frac{760 X 12}{720} \\\\V_2 = 12.7 L$

Therefore, V₂ is 12.7 L

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