Answer: Set with equal densities are:
15.2 g copper and 50.0 g copper ; 11.2 g gold and 14.9 g gold
Explanation:
Density is defined as mass of the substance present in unit volume of the substance.
It is an intensive property which means that two different masses of same substance will have same value of density under same conditions.
So, from the given samples with equal density are:
- 15.2 g copper and 50.0 g copper will have the same value density.
- 11.2 g gold and 14.9 g gold will have the same value density.
The answer is 0.18
Because the equation for finding the molarity of a solution is:
Moles divided by Liter of solution,
so, you dissolve 0.32 mol of KCL in 1759 ml of Water 1759 ml is 1.759 liters when you plug the numbers in you get 0.18
Hope this helps,
kwrob
Answer:
The correct answer is - the uterus.
Explanation:
The uterus or the womb is an organ that appears to be pear-shaped and it is hollow from inside where the fetus is developed and it is also called the birth canal. The uterus has two parts one is the cervix and the other is the corpus.
The cervix makes the lower part of the uterus and opens up into the vagina the external reproductive organ of the females. The corpus is the part that makes the main body of the uterus. The uterus is present between the bladder and rectum where the egg fertilized and implanted itself.
The pH of salt depends on the component acid and base that comprise them. For example, if the salt is made up of strong acid and weak base then, the salt is acidic. If the salt is formed from strong base and weak acid then, the salt is basic. For this item, NH4Cl is acidic and also Ca(NO3)2 is acidic.
Answer:
Random movements of the dye and water molecules cause them to bump into each other and mix. Thus, the dye molecules move from an area of higher concentration to an area of lower concentration. Eventually, they are evenly spread throughout the solution. This means the molecules have reached a dynamic equilibrium.
Instructure › katyisd › filesPDF
Diffusion and Osmosis
Explanation:
found this online. hope this helps
