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sattari [20]
2 years ago
10

How can you tell if a function is linear by looking at the graph or the equation​

Mathematics
1 answer:
MrMuchimi2 years ago
7 0
Every linear graph is just a straight line, so if there are any curves or unnatural shapes, than you know it is not linear. As for equations, if it can be shaped into y=mx+b where m and b are numbers, then it will be a linear equation.
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What is 63= 9k;6,7,8
OLEGan [10]
63 = 9k 

divide by 9 on each side to get k by itself 

k = 7
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3 years ago
Pls help I’ll give u 50 points for the right answer
Gwar [14]

Answer:

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Step-by-step explanation:

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Please solve 3(-4 + x) < -33
Dvinal [7]

<u><em>Answer:</em></u>

<u><em>x < -7</em></u>

<u><em>Step-by-step explanation:</em></u>

<em><u>Divide both sides by 3</u></em>

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Which expression is equivalent to (5^3)^2
Katarina [22]

Answer:

(5^3)^2 = 5^6 = 15625

<em>good luck, i hope this helps :)</em>

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%20x%5E%7B2%7D-10x%2B25%7D%2B25%2B12%5Csqrt%7Bx%7D%20%3D15%5Csqrt%7Bx%7D" id="TexFor
vodomira [7]

Step-by-step explanation:

\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x} \\  \\  \therefore \: \sqrt{ x^{2}-10x+ {5}^{2} }+25 =15\sqrt{x} - 12\sqrt{x}\\  \\  \therefore \: \sqrt{( x - 5)^{2}}+25 =3\sqrt{x}  \\  \\ \therefore \:  x - 5+ 25 = 3 \sqrt{x}  \\  \\ \therefore \: x + 20 = 3 \sqrt{x}  \\  \\ squaring \: both \: sides \\ (x + 20)^{2}  = ( {3 \sqrt{x} })^{2}  \\ \therefore \:  {x}^{2}  + 40x + 400 = 9x \\ \therefore \:  {x}^{2}  + 40x + 400  - 9x = 0 \\  \therefore \:  {x}^{2}  + 31x + 400  = 0 \\

8 0
3 years ago
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