Question

A small pool filled only with water will require an additional 300 gallons of water in order to be filled to 80% of its capacity. If pumping in these additional 300 gallons of water will increase the amount of water in the pool by 30%, what is the total capacity of the pool in gallons?A. 1000B. 1250C. 1300D. 1600E. 1625

Answer 1

Answer:

E

Explanation:

Let the total capacity of the pool be x

Let the initial volume of water in the pool be y

then;

300 + y =80% of x

300 + y = (80/100) * x

300 + y = 0.8x   ...........................equation 1

300 gallons of water increased the volume by 30x

y +300 = y +30% of y

300 = 0.3y

y=  (300/0.3)

y= 1000

substitute y into equation 1 to get x

300 + y = 0.8x

300 + 1000 = 0.8x

1300 =0.8x

x= (1300/0.8)

x= 1625 gallons