Ok so v is the velocity. Assuming it is constant, v = 2m/s
At 6 seconds x= 12.0m
Answer:
The b-b at rest will hit the ground first
Explanation:
When the first b-b is shot at angle it will first experience some horizontal force of air resistance before it experience another vertical force of resistance when going done while the second b-b only experiences the vertical force of resistance making reach the ground faster.
Answer:
0.67 m/s
Explanation:
Mass of car 1, m₁ = 5000 kg
Mass of car 2, m₂ = 10,000 kg
Initial speed of car 1, u₁ = 2 m/s
Final speed of car 2, u₂ = 0 (at rest)
We need to find the final velocity of both cars when inelastic collision occurs. The momentum will remain conserved in case of inelastic collision. Using the conservation of momentum. Let V is the final speed.

So, after the inelastic collision, they will move with a speed of 0.67 m/s.