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OLEGan [10]
3 years ago
10

A car leaves the pit after a refueling stop and accelerates uniformly to a speed of 62.2 m/s in 5.0 s to rejoin the race.

Physics
1 answer:
MakcuM [25]3 years ago
5 0

Answer:

The car's acceleration is: a = 12.44 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f} =  v_{o}+a*t

where:

Vf = final velocity = 62.2 [m/s]

Vo = initial velocity = 0 (because the car stars from the rest)

a = acceleration [m/s²]

t = time = 5 [s]

62.2 = 0 + a*5

a = 12.44 [m/s²]

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A gardener uses 1600 J of work to push a wheelbarrow for 45 seconds. How
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Un vagón de carga de 5000-kg se mueve a 2m/s e impacta a un vagón de 10000-kg que se encuentra en reposo. Después de la colisión
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Answer:

0.67 m/s

Explanation:

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Final speed of car 2, u₂ = 0 (at rest)

We need to find the final velocity of both cars when inelastic collision occurs. The momentum will remain conserved in case of inelastic collision. Using the conservation of momentum. Let V is the final speed.

m_1u_1+m_2u_2=(m_1+m_2)V\\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{5000\times 2}{(5000+10000)}\\\\V=0.67\ m/s

So, after the inelastic collision, they will move with a speed of 0.67 m/s.

6 0
3 years ago
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