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Vikentia [17]
2 years ago
14

Ratio of acceleration due to grabity and universal gravitational constant

Physics
1 answer:
creativ13 [48]2 years ago
3 0

Answer:

acceleration due to gravity = 9.8m/s^2

universal gravitational constant= 6.67×10 ^_11 nm^2 kg_2

now, ratio=9.8/6.67×10^_11.

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Estimate the distance (in cm) between the central bright region and the third dark fringe on a screen 5.00 m from two double sli
Artist 52 [7]

Answer:

y = 1.75 cm

Explanation:

In the double-slit experiment the equation for destructive interference is

           d sin tea = (m + ½)

λ

let's use trigonometry to find the angle

         tan θ = y / L

as all the experiment does not occur at small angles

          tan θ = sin θ / cos θ = sin θ = y / L

we substitute

        y = (m + 1/2 ) λ  L / d

we calculate

         y = (3 + ½) 500 10⁻⁹ 5.00 / 0.5 10⁻³

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5 0
2 years ago
A horizontal force of 24 N is being applied to a box on a level surface. The box is accelerating at the rate of 2.0 against a fr
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Answer:

For SI units the mass m = 5 kg.

Explanation:

The sum of all horizontal forces is must be equal to maₓ:

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maₓ = 10N

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7 0
3 years ago
In the equation for Ohm’s law what does I stand for?
Ket [755]
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3 0
3 years ago
What happens in the process of gravitational condensation?
marissa [1.9K]

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6 0
3 years ago
Read 2 more answers
A 1.2 kg hammer slams down on a nail at 5.0 m/s and bounces off at 1.0 m/s. If the impact lasts 1.0 ms, what average force is ex
Delvig [45]

Answer:

Explanation:

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F = m(vf - vi)/t

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F = 3000 N

7 0
2 years ago
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