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11111nata11111 [884]
3 years ago
13

Team A and Team B are competing against each other in a game of tug-of-war. Team A, consisting of 3 males and 3 females, decides

to line up male, female, male, female, male, female. The lineup that Team A chooses will be one of how many different possible lineups?
Mathematics
1 answer:
saul85 [17]3 years ago
4 0

Answer:  Team A will choose one of 36 possible lineups.

Step-by-step explanation:  Given that Team A and Team B are playing the game of tug-of-war.

Team A has 3 males and 3 females that decides to line up  male, female, male, female, male, female.

We are to find the number of possible lineups that Team A can make.

According to the given information,

number of options for the first position = 3,

number of options for the second position = 3,

number of options for the third position = 2,

number of options for the fourth position = 2,

number of options for the fifth position = 1

and

number of options for the sixth position = 1.

Therefore, the number of possible lineups by Team A is

n=3\times3\times2\times2\times1\times1=36.

Thus, Team A will choose one of 36 possible lineups.

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An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.
andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are E(1)= ^9C_2 places in which the other 2 red balls can be placed.

A red ball drawn third, there are E(3)= ^7C_2 places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are E(5)= ^5C_2 places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are E(7)= ^3C_2 places in which the other 2 red balls can be placed.

The total number of total event is S= ^{10}C_3

The probability that A selects the first red ball is

P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}

P(A \text{wins})=\frac{36+21+10+3}{120}

P(A \text{wins})=\frac{70}{120}

P(A \text{wins})=0.5833

6 0
3 years ago
So I finished the graph, But I need help making the table please help whoever answers correctly, I will mark brainliest 10. Corn
Monica [59]

Answer:

Here it is. The table is on the first one at the bottom.

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP ILL GIVE BRAINILEST ANSWER!
skelet666 [1.2K]

Answer:

Angle A=73

Step-by-step explanation:

5 0
3 years ago
Valerie ran Three and one-fourth laps yesterday, and her coach wants her to run Two and one-half times that many laps today. How
Maru [420]

Answer:

13/4 * 5/2

Step-by-step explanation:

In the question, it says that her coach wants her to run 2 1/2 TIMES the original 3/4 she had ran. Therefore, you would want to make the fractions into improper fractions, and then multiply, which is how you would get 13/4 * 5/2.

6 0
3 years ago
Describe two ways to solve the equation 2(4x-11)=10
lora16 [44]
One way is to:

First, multiply 2 by the term inside the parenthesis.

Second, add eleven on both sides.

Third, divide using 4x on both sides.

This will give you your first method.
7 0
3 years ago
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