Let's call the event of the red die to show a six as event A, and the event of the green die to show a six as event B.
The theoretical probability is defined as the ratio of the number of favourable outcomes to the number of possible outcomes. On both dices, we have 6 possible outcomes(the numbers from 1 to 6), with one favourable outcome(the number 6), therefore, the probabilities of those events are:
Each roll is independent from each other, then, the probability of both events happening simultaneously is given by their product:
Using the additive rule of probability, we have the following equation for our problem:
the probability that the red die shows a six or the green die shows a six is 11/36.
Answer:
two different ways this could be done.
Step-by-step explanation:
sin = 3/7
1 = sin²0 + cos²0
cos²0 = 1 - 9/49
cos²0 = 40/49
cos0 = √(40) / 7
since its in Quadrant 2 the sin is positive and cos is negative
cos0 = - √(40) / 7
Answer:
The correct option is 3. The value of x is 8 inches.
Step-by-step explanation:
It is given that Figure A is dilated by a scale factor of 1/2 to form Figure B. It means both figure are similar and corresponding sides of similar figures are proportional.
Multiply both sides by 16.
Since scale factor is 1/2, so we can directly say that the side length of image is half of the corresponding side of preimage.
The length of x is 8 inches. Therefore the correct option is 3.
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Step-by-step explanation:
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