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Vitek1552 [10]
3 years ago
8

When the glucose transport maximum is reached, _______.?

Chemistry
1 answer:
n200080 [17]3 years ago
8 0
Glucose is extracted in the urine and all of the glucose is reabsorbed. 
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Draw the skeletal (line-angle) structure for 2,2-dimethyl-4-propyloctane.
Allisa [31]

Answer :

Total carbons are in the structure = 13

Primary carbons are in the structure = 5

Secondary carbons are in the structure = 6

Tertiary carbons are in the structure = 1

Quaternary carbons are in the structure = 1

Explanation :

Primary carbon : It is a carbon atom that is bound to only 1 carbon atom.

Secondary carbon : It is a carbon atom that is bound to 2 carbon atom.

Tertiary carbon : It is a carbon atom that is bound to 3 carbon atom.

Quaternary carbon : It is a carbon atom that is bound to 4 carbon atom.

As we are given the name of compound is, 2,2-dimethyl-4-propyloctane.

In this compound, eight carbon are align in a straight line, two methyl group are attached at 2nd position of the carbon in main chain and a propyl group that is three membered carbon chain is attached at 4th position of the carbon in main chain.

The given compound skeletal structure is shown below.

6 0
3 years ago
An object has a mass of 20 g and a volume of 5 mL what is the objects density
IceJOKER [234]
<span>4000 kilogram/cubic meter
http://www.calculator.net/density-calculator.html?cdensity=&cdensityunit=kilogram%2Fcubic+meter&cvol...
</span>
7 0
3 years ago
Q<br> 1 What is rusting?
blondinia [14]

Answer:

Rust is a chemical reaction (oxidation) of iron that occurs over a period of time as the bare metal surface comes in contact with oxygen present in the air or water. Rust "eats" away the metal, rendering it weak and fragile. ... Avoid contact with water or moisture.

8 0
3 years ago
Read 2 more answers
Please help me
Wittaler [7]

Answer:

pH = 6.999

The solution is acidic.

Explanation:

HBr is a strong acid, a very strong one.

In water, this acid is totally dissociated.

HBr + H₂O  →  H₃O⁺  +  Br⁻

We can think pH, as - log 7.75×10⁻¹² but this is 11.1

acid pH can't never be higher than 7.

We apply the charge balance:

[H⁺] = [Br⁻] + [OH⁻]

All the protons come from the bromide and the OH⁻ that come from water.

We can also think [OH⁻] = Kw / [H⁺] so:

[H⁺] = [Br⁻] + Kw / [H⁺]

Now, our unknown is [H⁺]

[H⁺] =  7.75×10⁻¹² + 1×10⁻¹⁴ / [H⁺]

[H⁺] = (7.75×10⁻¹² [H⁺] + 1×10⁻¹⁴) /  [H⁺]

This is quadratic equation:  [H⁺]² - 7.75×10⁻¹² [H⁺] - 1×10⁻¹⁴

a = 1 ; b = - 7.75×10⁻¹² ; c = -1×10⁻¹⁴

(-b +- √(b² - 4ac) / (2a)

[H⁺] = 1.000038751×10⁻⁷

- log [H⁺] = pH → 6.999

A very strong acid as HBr, in this case, it is so diluted that its pH is almost neutral.

8 0
3 years ago
Consider separate 1.0-L samples of He(g) and UF6(g), both at 1.00 atm and containing the same number of moles. What ratio of tem
diamong [38]
V =  \sqrt{x} 3 * R * T / MW

V = RMS velocity

R = 8.3145 J/K*mole

T = Temperature K

MW = Molecular weigh in Kg
3 0
3 years ago
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