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3 years ago

When the glucose transport maximum is reached, _______.?

Chemistry

1 answer:

n200080 [17]3 years ago

8 0

Glucose is extracted in the urine and all of the glucose is reabsorbed.

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4 years ago

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Vitamin C has the formula CxHyOz. You burn 0.486 g of the compound in a combustion analysis chamber and isolate 0.728 g of CO2 a

-Dominant- [34]

Answer:

$C_3H_4O_3$

Explanation:

Hello there!

In this case, according to the given information derived from the combustion analysis, it turns out possible for us to realize that all the carbon comes from the CO2 and all the hydrogen from the H2O, it means we can calculate their moles in the vitamin C as shown below:

$n_C=0.728gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2}=0.0165molC\\\\n_H= 0.198gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O}=0.0220molH$

Next, we calculate the grams and moles of oxygen from the grams of C and H in the sample:

$m_O=0.486g-0.0165molC*\frac{12.01gC}{1molC} -0.0220molH*\frac{1.01gH}{1molH}\\\\m_O=0.266gO\\\\n_O=0.266gO*\frac{1molO}{16.00gO} =0.0166molO$

Then, we divide the moles of C, H, O by 0.0165 as the fewest moles in order to calculate the correct mole ratios:

$C=\frac{0.0165}{0.0165}= 1\\\\H=\frac{0.0220}{0.0165}= 1.33\\\\O=\frac{0.0166}{0.0165}= 1$

Finally, we turn them into whole number by multiplying by 3 so that the empirical formula is:

$C_3H_4O_3$

Regards!

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3 years ago

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