The answer to the question is radium (Ra)
261.162 grams. Use the equation n=M÷Mr.
The mass in grams of butane at standard room temperature is 53.21 grams.
<h3>How can we determine the mass of an organic substance at room temperature?</h3>
The gram of an organic substance at room temperature can be determined by using the ideal gas equation which can be expressed as:
PV = nRT
- Pressure = 1.00 atm
- Volume = 22.4 L
- Rate = 0.0821 atm*L/mol*K
- Temperature = 25° C = 298 k
1 × 22.4 L = n × (0.0821 atm*L/mol*K× 298 K)
n = 22.4/24.4658 moles
n = 0.91556 moles
Recall that:
- number of moles = mass(in grams)/molar mass
mass of butane = 0.91556 moles × 58.12 g/mole
mass of butane = 53.21 grams
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The rate law depicts the effect of concentration on reaction rate. Second mechanism 2NO(g) ⇄ N₂O₂(g) [fast], N₂O₂(g) + O₂(g) → 2NO₂(g) [slow] is most reasonable. Thus, option b is correct.
<h3>What is rate law?</h3>
Rate law and equation give the rate at which the reaction takes place under the influence of the concentration of the reactants. The balanced chemical reaction is given as,
2NO(g) + O₂(g) → 2NO₂(g)
The rate of the equation is given as,
rate = k [NO]² [O₂]
In a multi-step chemical reaction, the slowest step is the rate-determining step. The second mechanism is given as,
2NO (g) → N₂O₂ (g) [fast]
N₂O₂(g) +O₂(g) → 2NO₂ (g) [slow]
Rate is given as,
rate = k [N₂O₂] [O₂]
Therefore, option b. the second mechanism is the most reasonable.
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Answer: a. 0.26mol
b. 0.000479mol
c. 1.12mol
Explanation: Please see attachment for explanation
