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3 years ago

Evaluate C(8, 2). 56 28 40,320 20,160

Mathematics

1 answer:

algol133 years ago

3 0

Answer:

option B

Step-by-step explanation:

Given in the question,

C(8,2)

Formula to use

here n = 8

r = 2

We have to calculate combinations of 8 object taken 2 at a time, then

C(8,2)

8C2

8! / 2! * (8 - 2)!

$\frac{8*7*6*5*4*3*2*1}{2*1(6!)}$

$\frac{8*7*6*5*4*3*2*1}{2*1(6*5*4*3*2*1)}$

$\frac{8*7}2$

56/2

So, 8C2 = 28

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telo118 [61]

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2 years ago

Apply the distributive property to factor out the greatest common factor. 32 + 44 = 32+44=32, plus, 44, equals

ICE Princess25 [194]

Answer:

4 is the largest number that is common to both 32 and 44. Factoring it out looks like this: 4(8 + 11) = 4(8 + 11). That's weird to me but all textbooks begin that process just that same way.

Step-by-step explanation:

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3 years ago

Read 2 more answers

The lengths of the legs of a right triangle are consecutive even integers. The hypotenuse is 58 inches. What is the sum of the l

miskamm [114]

Answer:

82 inches

Step-by-step explanation:

The difference between consecutive even integers is 2, thus

let the legs be n and n + 2

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

n² + (n + 2)² = 58² ← expand and simplify left side

n² + n² + 4n + 4 = 3364 ( subtract 3364 from both sides )

2n² + 4n - 3360 = 0 ( divide all terms by 2 )

n² + 2n - 1680 = 0 ← in standard form

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Equate each factor to zero and solve for n

n + 42 = 0 ⇒ n = - 42

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But n > 0 ⇒ n = 40

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3 years ago

Help!<br><br> If a sphere has a radius of 8mm, what is its volume? (Show work)

babymother [125]

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3 years ago

A regular octagon has a radius of 6 ft and a side length of 4. 6 ft. A regular octagon has a radius of 6 feet and side lengths o

skad [1K]

The regular octagon has eight equal sides. Then the area of the regular octagon of side length be 4.6 is 102 ft².

<h3>What is a regular octagon?</h3>

It is a polygon that has eight equal sides. In a regular octagon, the opposite sides are parallel. And its diagonals are also equal and intersect at mid-point.

Given

A regular octagon has a radius of 6 ft and a side length of 4.6 ft.

We know the formula for the regular octagon.

Area of the regular octagon = 2(1 + $\sqrt{2}$ ) a²

Where a be the side of a regular octagon.

Then the area of the regular octagon will be.

$\rm Area = 2 (1+\sqrt{2} ) a^2\\\\Area = 2*(1 + 1.414) *4.6^2\\\\Area = 2 * (2.414)* 21.16\\\\Area = 102.16$

Thus, the area of the regular octagon of side length be 4.6 is 102 ft².

More about the regular octagon link is given below.

brainly.com/question/858868

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2 years ago