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pentagon [3]
3 years ago
14

Which change in the h+ ion concentration of an aqueous solution represents a decrease of one unit on the ph scale?

Chemistry
1 answer:
melisa1 [442]3 years ago
6 0
The answer would be a tenfold increase<span>
The pH scale is calculated based on the concentration of H+ ion in the solution. The formula is using log10, so to decrease 1 unit from the scale it will be 10^1= 10 fold of increase. For 2 </span>unit, you will need 10^2= 100 fold of increase.
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A client with tongue occlusion has loss of gag reflex and alterations in level of consciousness. The blood gas test shows oxygen
siniylev [52]

Answer:

answer is given below

Explanation:

Upper airway obstruction with tongue closure may be associated with damage Changes in alertness and level of consciousness. Clients with severe hypoxia (O2)

Saturation of 40 mm Hg and this is an emergency for hypercapnic (CO2 saturation of 75 mm Hg)

Tracheotomy for relief in 2 minutes. Laryngeal repair is performed to prevent laryngeal.  

Cover cartilage cover. Clears the upper airway obstruction due to abdominal thrust maneuvering  Foreign body. Autoradiating positive airway pressure resets full pressure during breathing

Users with severe sleep apnea

7 0
3 years ago
Sodium hydroxide (NaOH) and hydrochloric acid (HCl) combine to make table salt (NaCl) and water (H2O). Which equation is balance
Art [367]

The equation that is balanced among the given options is the first equation NaOH + HCl → NaCl + H2O

From the question,

We are to determine which of the options gives a balanced equation for the reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl) to make table salt (NaCl) and water (H₂O)

To do this, we will check which of the given equations is balanced, by checking the equations one after the other.

First, we will define what is meant by balanced equation.

Balanced equations are those whose coefficients result in equal numbers of atoms for each element in the reactants and products

  • For NaOH + HCl → NaCl + H2O

On the reactants side

Na = 1

O = 1

H = 2

Cl = 1

On the products side

Na = 1

O = 1

H = 2

Cl = 1

Since equal number of atoms of each element are present at both the reactants and products sides, then the equation is balanced

  • For 2NaOH + 2HCl → 2NaCl + H2O

On the reactants side

Na = 2

O = 2

H = 4

Cl = 1

On the products side

Na = 2

O = 1

H = 2

Cl = 2

The number of atoms of each element present at the reactants side and that present at products side are not equal.

∴ The equation is not balanced

  • For 2NaOH + HCl → NaCl + H2O

On the reactants side

Na = 2

O = 2

H = 3

Cl = 1

On the products side

Na = 1

O = 1

H = 2

Cl = 1

The number of atoms of each element present at the reactants side and that present at products side are not equal.

∴ The equation is not balanced

  • For NaOH + 2HCl → NaCl + H2O

On the reactants side

Na = 1

O = 1

H = 2

Cl = 2

On the products side

Na = 1

O = 1

H = 2

Cl = 1

The number of atoms of each element present at the reactants side and that present at products side are not equal.

∴ The equation is not balanced

Hence, the equation that is balanced is the first equation NaOH + HCl → NaCl + H2O

Learn more here: brainly.com/question/17015942

6 0
2 years ago
Read 2 more answers
When Iodine-131 emits a β particle (beta particle), what nuclide is produced? *
k0ka [10]

When Iodine-131 emits a β particle will produce Xe-131

<h3>Further explanation </h3>

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

  • alpha α particles ₂He⁴
  • beta β ₋₁e⁰ particles
  • gamma particles ₀γ⁰
  • positron particles ₁e⁰
  • neutron ₀n¹

So for reaction Iodine-131 :

\tt _{53}^{131}I\rightarrow _{-1}^0\beta +_{54}^{131}Xe

5 0
3 years ago
Read 2 more answers
Which of these is a bacteria?<br><br> E-coli<br> HIV<br> Yeast<br> Zika
ZanzabumX [31]
<h3>Answer:</h3><h3></h3><h2>E. Coli </h2>

<h2>its a easy and faster answer to look at (;</h2>

5 0
3 years ago
Read 2 more answers
Classify the reaction by their type. Note there may be more than one way to classify a reaction.
Nadya [2.5K]

Answer:

Redox reaction and single displacement

Explanation:

This reaction is first of all a redox reaction. A redox reaction is a reaction that involves both oxidation and reduction. Oxidation involves increase in oxidation number while reduction involves decrease in oxidation number.

Copper (Cu) had an oxidation number of "0" as a reactant but had an oxidation number of "2+" in the product [Cu(NO₃)₂] hence oxidation occurred.

Nitrogen (N) had an oxidation number of "5+" in the reactant (HNO₃) but had an oxidation number of "4+" in the product (NO₂) hence reduction also occurred.

Also, from the reaction, it can be deduced that copper (Cu) displaced hydrogen (H) from the nitric acid (HNO₃) solution to form copper (II) nitrate [Cu(NO₃)₂]. It should be noted that copper can displace hydrogen because it is higher than hydrogen in the electrochemical series. Hence, this reaction can also be called a single displacement reaction. A single displacement reaction is a reaction in which an atom of an element replaces another atom in a compound (as seen in the equation given in the question).

3 0
3 years ago
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