Solution:
Molality:-It is a measure of the concentration of a solute in a solution in terms of amount of substance in a specified amount of mass of the solvent
Therefore,
Molality = moles solute / kg solvent
Therefore kg solvent = moles solute / molality
moles solute = mass / molar mass
= 25.31 g / 101.1 g/mole
= 0.2503 mole
kg solvent = 0.2503 mole / 0.1982 m
= 1.263 kg
= 1263 g
This is the required answer.
The balanced chemical equation between iron and oxygen to produce iron (III) oxide is,

Mass of Fe = 227.8 g
Moles of Fe = 
Mass of oxygen = 128 g
Moles of 
Calculating the limiting reactant: The reactant that produces the least amount of product will be the limiting reactant.
Mass of iron (III) oxide produced from Iron = 
Mass of iron (III) oxide produced from oxygen=
Iron (Fe) produces the least amount of the product iron (III) oxide. So, Fe is the limiting reactant.
Answer:
left to right across a period when it decreases and when it increases top to bottom in a group,
hope i helped
There are 1000 mg in 1 g
and there are 1000 g in 1 kg
Start by converting 1.34 mg to grams by dividing 1.34 mg by 1000 g = 0.00134 g
Then convert 0.00134 g to kg by dividing 0.00134 g by 1000 kg = 1.34×10^-6 kg OR 0.00000134 kg