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pentagon [3]
3 years ago
14

Which change in the h+ ion concentration of an aqueous solution represents a decrease of one unit on the ph scale?

Chemistry
1 answer:
melisa1 [442]3 years ago
6 0
The answer would be a tenfold increase<span>
The pH scale is calculated based on the concentration of H+ ion in the solution. The formula is using log10, so to decrease 1 unit from the scale it will be 10^1= 10 fold of increase. For 2 </span>unit, you will need 10^2= 100 fold of increase.
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3 0
1 year ago
Please help i dont understand it
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Answer:-  solution boiling point = 102.23 degree C (102 degree C with three sig figs).

Solution:- When a non volatile solute is added to a solvent then boiling point increases. Elevation in boiling point is directly proportional to the molality of the solution.

The equation is:

\Delta T_b=i*k_b*m

where, \Delta T_b is the elevation in boiling point, i is the Van't hoff factor, k_b is the molal elevation constant and m is the molality.

Value of i is 1 as ethylene glycol is a covalent molecule that does not break to give ions. k_b for water is \frac{0.512^0C}{m} .

We can calculate the molality from the given grams of ethylene glycol and liters of water as molality is moles of solute per kg of solvent.

Molar mass of ethylene glycol is 62 gram per mol and density of water is 1.00 kg per liter.

2.50L(\frac{1kg}{1L})

= 2.50 kg

Let's calculate the moles of ethylene glycol.

675g(\frac{1mol}{62g})

= 10.9 mol

molality of the solution = \frac{10.9mol}{2.50kg}

= 4.36m

Let's plug in the values in the equation we have on the top for elevation in boiling point.

\Delta T_b=4.36m(\frac{0.512^0C}{m})

= 2.23^0C

Boiling point of pure water is 100 degree C. So, the boiling point of the solution = 100 + 2.23 = 102.23 degree C

(If we fix the three sig figs then it could be written as 102 degree C.)

4 0
3 years ago
Read 2 more answers
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<h2><u>Answer:</u></h2>

The correct answer is A) 1.04 mol Cu

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Explanation:

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