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Roman55 [17]
1 year ago
13

A chemist makes four successive ten-fold dilutions of 1.0x10⁻⁵ M HCl. Calculate the pH of the original solution and of each dilu

ted solution (through 1.0x10⁻⁹ M HCl).
Chemistry
1 answer:
ra1l [238]1 year ago
7 0

The pH of the original solution is 7.0.

<h3>What is pH?</h3>
  • An aqueous solution's acidity or basicity can be determined using the pH scale, which previously stood for "potential of hydrogen."
  • In comparison to basic or alkaline solutions, acidic solutions are measured to have lower pH values.
  • You need to know the hydronium ion concentration in moles per liter to determine the pH of an aqueous solution (molarity).
<h3>Calculation of pH:</h3>

At 25°C, in pure water [H₃O⁺] = 1.0 × 10⁻⁷ M

HCl after four successive ten-fold dilution = (1.0 × 10⁻⁵ M) × (1/10)⁴

= 1.0 × 10⁻⁹ M

[H₃O⁺] from HCl = 1.0 × 10⁻⁹ M ≪ 1.0 × 10⁻⁷ M

Hence, the pH of solution is almost entirely depends on the dissociation of water.

pH of the original solution = -log(1.0 × 10⁻⁷) = 7.0

Hence, the pH of the original solution is 7.0.

Learn more about pH here:

brainly.com/question/2288405

#SPJ4

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How many grams of Fe3O4 are required to react completely with 300 grams of H2?
vekshin1

Answer:

2023.04 g

Explanation:

Magnetite reacts with hydrogen to produce Iron metal and steam. Steam instead of water is produced as the reaction occurs at temperatures above the boiling point of water.

Fe₃O₄ + 4 H₂ → 3 Fe +4 H₂O

From the equation, 1 mole of Fe₃O₄ reacts with 4 moles of H₂.

69.76 grams of H₂ has the following number of moles.

Number of moles= mass/RAM

=69.76/2

=34.88 moles.

The reaction ratio of Fe₃O₄ to H₂ is 1:4

Thus number of moles of magnetite= (1×34.88)/4

=8.72 moles.

Mass= moles × molecular weight

=8.72 moles × (56×3+16×4)

=2023.04 grams

8 0
3 years ago
A student placed 18.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
mamaluj [8]

Answer:

1.30464 grams of glucose was present in 100.0 mL of final solution.

Explanation:

Molarity=\frac{moles}{\text{Volume of solution(L)}}

Moles of glucose = \frac{18.5 g}{180 g/mol}=0.1028 mol

Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = \frac{0.1028 mol}{0.1 L}=1.028 mol/L

A 30.0 mL sample of above glucose solution was diluted to 0.500 L:

Molarity of the solution before dilution = M_1=1.208 mol

Volume of the solution taken = V_1=30.0 mL

Molarity of the solution after dilution = M_2

Volume of the solution after dilution= V_2=0.500L = 500 mL

M_1V_1=M_2V_2

M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}

M_2=0.07248 mol/L

Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

0.07248 mol/L=\frac{\text{moles of glucose}}{0.1 L}

Moles of glucose = 0.07248 mol/L\times 0.1 L=0.007248 mol

Mass of 0.007248 moles of glucose :

0.007248 mol × 180 g/mol = 1.30464 grams

1.30464 grams of glucose was present in 100.0 mL of final solution.

4 0
3 years ago
In the process of preparing liquid air for fractional distillation, one fraction will be separated as a solid. What is the chemi
makvit [3.9K]

Answer:

carbon dioxide CO₂

Explanation:

Each gas has a characteristic boiling point. You can separate a random sample of gases by gradually cooling the sample until each component gas liquifies. Some compounds, such as CO₂ never liquify. Instead, they turn directly into solids.

3 0
2 years ago
GoOd MoRnInG <br> EvErY OnE <br> BlA BlA BlA BlA
azamat

Answer:

you too ^^

Explanation:

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3 years ago
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The metalloid that has five valence electrons in the fourth electron shell is
insens350 [35]
Arsenic, I believe. Metalloids fall in between metals and nonmetals (usually on the bold line separating the two on the periodic table). And since the metalloid in question has four electron shells and five valence electrons in the outermost shell, you can see that this element is arsenic

3 0
3 years ago
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