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ivanzaharov [21]
2 years ago
8

Identify which location in the periodic table you would have the largest atomic radii.

Chemistry
1 answer:
bearhunter [10]2 years ago
5 0

Answer:

left to right across a period when it decreases and when it increases top to bottom in a group,

hope i helped

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Write a chemical equation for nh4+(aq) showing how it is an acid or a base according to the arrhenius definition.
GuDViN [60]

An Arrhenius acid by definition dissociates in water to form H3O+ (or H+) ions while an arrhenius base dissociates in water to form OH- ions.

NH4+(aq) can be categorised as an arrhenius acid since it releases H3O+ ions in aqueous media

NH4+(aq) + H2O (aq) ↔ NH3 (aq) + H3O+(aq)

3 0
3 years ago
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Helium has a density of 1.79 x 10-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate t
LenaWriter [7]
The density of He is 1.79 x 10⁻⁴ g/mL
In other words in 1 mL there's 1.79 x 10⁻⁴ g of He. 
To fill a volume of 6.3 L the mass of He required 
    = 1.79 x 10⁻⁴ g/mL * 6300 mL
   = 11 277 * 10⁻⁴ g
  Therefore mass of He required = 1.1277 g of He
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What would the formula of gallium<br> bromide be?
Free_Kalibri [48]
GaBr3

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Bromine= Br
Bromide=Br3
5 0
3 years ago
In a real system of levers, wheels, or pulleys, the AMA is less than the IMA because _____.
kodGreya [7K]

Answer:

the work input is depented on the work output

Explanation:

7 0
3 years ago
Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid
slava [35]

Answer:

pH of resulting solution = 7.98

Explanation:

The balanced equation  

HA + NaOH - Na+ + A- + H2O

Number of moles of A = Number of moles of HA  = Number of moles of NaOH

= 35.8/1000 * 0.020 = 0.000716 mol

Initial concentration of A = 0.000716/0.0608 = 0.01178 M

pKb = 14 – pKa = 14 -3.9 = 10.1

Kb = 10^{-Kb} = 10^{-10.1} = 7.943 * 10^-11

Kb = [HA][OH-]/[A-]

Kb = a^2/(0.01178 -a) = 7.943 * 10^-11

a^2 + 7.943 * 10^-11 a – 9.357 * 10^-13 = 0

a = 9.673 * 10^-7

OH- = a = 9.673 * 10^-7 M

pOH = -log [OH-] = -log (9.673 * 10^-7) = 6.02

pH = 14-6.02 = 7.98

8 0
2 years ago
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