The required moles of AgBr precipitate produced by given moles of silver nitrate is 0.0123.
<h3>How do we calculate moles from molarity?</h3>
Molarity of any solution is define as the moles of solute present in per liter of the solution and it will be represented as:
M = n/V
Given that, molarity of AgNO₃ = 0.250M
Volume of AgNO₃ = 49.5mL = 0.0495L
Moles of AgNO₃ = (0.25)(0.0495) = 0.0123mol
Given chemical reaction is:
2AgNO₃(aq) + CaBr(aq) → 2AgBr(s) + Ca(NO₃)₂(aq)
As it is mention that CaBr is present in excess quantity and AgNO₃ is the limiting reagent so the formation of precipitate will depend on the AgNO₃.
From the stoichiometry of the reaction, it is clear that:
2 moles of AgNO₃ = produces 2 moles of AgBr
0.0123 moles of AgNO₃ = produces 2/2×0.0123=0.0123 moles of AgBr
Hence 0.0123 is the required moles of precipitate.
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Answer:
I think it's B
Explanation:
I think it is b because if the number is positive the zeroes will be on the left so you move the decimal to the right to get rid of the zeroes.
Answer:
7.5 gm left
Explanation:
Bismuth-210 has a half life of 5 days
15 days is 15/5 = 3 half lives
since half the amount is left in 5 days or 1 half life
(1/2) x (1/2) x (1/2) the staring amount would be left in
3 half lives. so 1/8 is left
(1/8) x 60.0 = 7.5 gm left
Answer:
- <em><u>Passive solar energy</u></em>
Explanation:
First of all, you must know that you if you put an egg on a sidewalk you are dealing with energy from the Sun, i.e. solar energy, while geothermal energy is energy that comes from the inner of the Earth and biomass energy comes from plant or animal material.
The term passive solar energy refers to the fact that the energy of the sun is used directly for the intended task, which in this case is to cook the egg.
The term active solar energy refers to the fact that the energy of the Sun is converted into a different form of energy and then used for your purpose. For instance, if the energy of the Sun were used to produce electricity and then this electricity used to cook the egg, you would be using an acitve solar energy.
Answer:
The calorimeter constant is = 447 J/°C
Explanation:
The heat absorbed or released (Q) by water can be calculated with the following expression:
Q = c × m × ΔT
where,
c is the specific heat
m is the mass
ΔT is the change in temperature
The water that is initially in the calorimeter (w₁) absorbs heat while the water that is added (w₂) later releases heat. The calorimeter also absorbs heat.
The heat absorbed by the calorimeter (Q) can be calculated with the following expression:
Q = C × ΔT
where,
C is the calorimeter constant
The density of water is 1.00 g/mL so 50.0 mL = 50.0 g. The sum of the heat absorbed and the heat released is equal to zero (conservation of energy).
Qabs + Qrel = 0
Qabs = - Qrel
Qcal + Qw₁ = - Qw₂
Qcal = - (Qw₂ + Qw₁)
Ccal . ΔTcal = - (cw . mw₁ . ΔTw₁ + cw . mw₂ . ΔTw₂)
Ccal . (30.31°C - 22.6°C) = - [(4.184 J/g.°C) × 50.0 g × (30.31°C - 22.6°C) + (4.184 J/g.°C) × 50.0 g × (30.31°C - 54.5°C)]
Ccal = 447 J/°C