Answer:
37.5 moles of O2 needed
Explanation:
2 moles of C6H6 need 15 moles of O2
5/2 * 15 = 37.5 of O2 needed
The answer is; relative dating
Through relative dating, rock layers are able to be sequenced with regards to their ages relative to each other. This, therefore, does not determine the absolute age of the rock layers (absolute dating). Techniques used in relative dating include stratigraphy and biostratigraphy that determine which layer is older than the other. In absolute dating, methods employed are carbon-dating and radiometric dating.
Answer:
B.) P4
Explanation:
Step 1: Convert 25.0 grams of phosphorus into moles of phosphorous:
25 g P4 x 1 mol P4/123.90 g P4 = 0.202 mol P4
Step 2: Convert 0.202 mol P4 into moles of O2 using their stoichiometric ratios:
0.202 mol P4 x 5 mol O2/1 mol P4 = 1.01 mol O2
Step 3: Convert 1.01 mol O2 into grams of O2:
1.01 mol O2 x 31.98 g O2/1 mol O2 = 32.3 g O2
Because 25.0 grams of phosphorous only needs 32.3 grams of oxygen to react, phosphorous will be the limiting reactant, as after the 25.0 grams of phosphorous is used up, there will still be 17.7 grams of oxygen leftover (excess reactant).
Because the reaction cannot occur without more phosphorous to react with the 17.7 grams of oxygen remaining, P4 is the limiting reactant.
AB + C -> A + BC
A and C are usually metals, and B is usually a polyatomic anion.
