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zysi [14]
3 years ago
10

Which of the following is most likely the next step in the series?

Mathematics
2 answers:
kirza4 [7]3 years ago
6 0

Answer:

D

Step-by-step explanation:

The pattern most likely goes blue, red, blue, red, etc. Therefore, it will be a red answer. Then, look at the count of the lines. You know that the next one will have four lines based on the 3 previous images. Lastly, (this is how my brain just works and it could be wrong) there are two vertical lines. I would think it would follow the pattern and be 2 horizontal lines next.

Hope this helps:) Have a good rest of your day!

Serggg [28]3 years ago
5 0

Answer:

the answer is D

Step-by-step explanation:

the color changes aswell in the sequence

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Is a triangle with 3m 2m 4m a right triangle
lys-0071 [83]

Answer:

Step-by-step explanation:

No it’s not because 4+9 = 16

And 13 < 16 when it has to be 16=16 therefore it is anything but a right triangle

4 0
3 years ago
Hannah has $2 worth of dimes and quarters. She has a total of 17 dimes and quarters altogether. By following the steps below, de
sineoko [7]

Answer:

2 quarters and 15 dimes

Step-by-step explanation:

15 dimes = $1.50

2 quarters = $0.50

$1.50+$0.50=$2.00

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3 years ago
Solve using the pathagorean theorem​
Sergio039 [100]

Answer:

A^(2) + B^(2) = C^(2)?????????????

Step-by-step explanation:

that's an isosceles triangle, not a right-angle triangle

8 0
2 years ago
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
3 years ago
I NEED HELP FAST PLEASE :)
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Answer:945

Step-by-step explanation:

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