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GenaCL600 [577]
3 years ago
8

HELP HelP HELP HELP HELP!!!!

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
5 0
M = 1.2*e^{0.25*t} + 0.13
If M = 19,
ln((19-0.13)/1.2)/.25 = t
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Evaluate each expression by (1) using the Distributive Property and (2) evaluating inside the parentheses first.
galina1969 [7]

Answer:

can u explain more

Step-by-step explanation:

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2 years ago
I JUST NEED THESE 3 QUESTIONS
Sidana [21]

Answer:  

 

1.     What is the period and the amplitude of the sine function representing the position of the band members as they begin to play?

Answer:  Amplitude is 80 ft, period is 60 ft.

 

2.     Edna is sitting in the stands and is facing Darla. Edna observes that sine curve begins by increasing at the far left of the field. What is the equation of the sine function representing the position of band members as they begin to play?

Answer:  y = 80cos(x*π/30)+80

 

3.     As the band begins to play, band members move away from the edges, and the curve reverses so that the function begins at the far left by decreasing. Darla does not move. The sine curve is now half as tall as it was originally. What is the equation of the sine curve representing the position of the band members after these changes?

Answer: y = 40cos(x*π/30)+80

 

4.     Next, the entire band moves closer to the edge of the football field so that the sine curve is in the lower half of the football field from Edna’s vantage point. What is the equation of the sine curve representing the position of the band members after these changes?

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Step-by-step explanation:

8 0
3 years ago
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iren2701 [21]

Answer:

Step-by-step explanation:

a°=180°-36°=144° b°=180°-113°=67°

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marin [14]

Answer:

y=-3x+5

Explanation:

Given a line L such that:

• L has y-intercept (0,5); and

,

• L is perpendicular to the line with equation y=(1/3)x+1.

We want to find the equation of the line in the slope-intercept form.

The slope-intercept form of the equation of a straight line is given as:

\begin{equation} y=mx+b\text{ where }\begin{cases}m={slope} \\ b={y-intercept}\end{cases} \end{equation}

Comparing the given line with the form above:

y=\frac{1}{3}x+1\implies Slope,m=\frac{1}{3}

Next, we find the slope of the perpendicular line L.

• Two lines are perpendicular if the product of their slopes is -1.

Let the slope of L = m1.

Since L and y=(1/3)x+1 are perpendicular, therefore:

\begin{gathered} m_1\times\frac{1}{3}=-1 \\ \implies Slope\text{ of line L}=-3 \end{gathered}

The y-intercept of L is at (0,5), therefore:

y-intercept,b=5

Substitute the slope, m=-3, and y-intercept, b=5 into the slope-intercept form.

\begin{gathered} y=mx+b \\ y=-3x+5 \end{gathered}

The equation of line L is:

y=-3x+5

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How do I find the direction of the rotation and the magnitude ​
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