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GenaCL600 [577]
3 years ago
8

HELP HelP HELP HELP HELP!!!!

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
5 0
M = 1.2*e^{0.25*t} + 0.13
If M = 19,
ln((19-0.13)/1.2)/.25 = t
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Θ is an acute angle and cosecant theta equals nine halves commacscθ= 9 2, find secant ((pi over 2) minus theta) .sec π 2−θ. do n
Ronch [10]
?????????IM NOT SUREEEE
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Solve equation:<br><img src="https://tex.z-dn.net/?f=y%20%2B%20%20%5Cfrac%7B7%7D%7B8%7D%20%20%3D%20%20%5Cfrac%7B3%7D%7B8%7D%20"
Gala2k [10]

Answer: y = -1/2

Step-by-step explanation:

Subtract both sides by 7/8

y = 3/8 - 7/8

Then combine like terms

y = -4/8

Then simplify

y = -1/2

4 0
3 years ago
I need number 2 I need help fast
Semmy [17]

Answer:

B. 70

Step-by-step explanation:

<h3><u>look at the smaller triangle</u></h3>

its dimensions are :

45 , 35 , 24

<h3><u>look at the bigger triangle ( this includes the dimensions of the smaller one)</u></h3>

its dimensions are :

45 + 45 ,  x , 24 + 24

= 90 , x  , 48

from the dimensions given we can notice that :

<em>bigger triangle dimensions are  = 2 * smaller triangle dimensions</em>

<em></em>

therefore to find the value of x :

x = 35 * 2

<h3><u>x = 70</u></h3>

<u />

<h3><u>hence the answer is B ) 70 </u></h3>
4 0
3 years ago
A contractor developed a multiplicative time-series model to forecast the number of contracts in future quarters, using quarterl
dusya [7]

There is a missing content in the question.

After the statements and before the the options given; there is an omitted content which says:

Referring to Table 16-5, in testing the coefficient of X in the regression equation (0.117) the results were a t-statistic of 9.08 and an associated p-value of 0.0000. Which of the following is the best interpretation of this result?

Answer:

C. The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05).

Step-by-step explanation:

From the given question:

The resulting regression equation can be represented as:

\hat Y = 3.37 + 0.117 X - 0.083 Q_1 + 1.28 Q_2 + 0.617Q_3

where;

the estimated number of contracts in a quarter X is the coded quarterly value with X = 0

the first quarter of 2010 Q1 is a dummy variable equal to 1 in the first quarter of a year and 0 otherwise

Q2 is a dummy variable equal to 1 in the second quarter of a year and 0 otherwise

Q3 is a dummy variable equal to 1 in the third quarter of a year and 0 otherwise

Our null and alternative hypothesis can be stated as;

Null hypothesis :

H_0 :  The quarterly growth rate in the number of contracts is not  significantly different from 0% (? = 0.05)

H_a:  The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

The decision rule is to reject the null hypothesis if the p-value is less than 0.05.

From the missing omitted part we added above; we can see that the   t-statistics value = 9.08 and the p-value = 0.000 .

Conclusion:

Thus; we reject the null hypothesis and accept the alternative hypothesis. i.e

The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

4 0
3 years ago
Mrs. Miller claims that 10% of the marbles in the jar are purple. Do the students have statistically significant evidence that t
Keith_Richards [23]

Answer: C: Yes

Step-by-step explanation:

C on edge 2021

4 0
3 years ago
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