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grandymaker [24]
3 years ago
11

A red car of mass m is heading north (direction 0°). It collides at an intersection with a yellow car of mass 1.3m heading east

(direction 90°). Immediately after the collision, the cars lock together and travel at in direction 42°. What is the speed of the yellow car just before the collision?
Physics
1 answer:
Degger [83]3 years ago
6 0
After the collision, the momentum to the north comes completely from the red car, and the momentum to the east comes completely from the yellow car. Suppose the initial velocity of red car is v1, and yellow car is v2. The momentum of red car is v1*m, and yellow car is v2*1.3m. Since the cas travel in direction 42, we know that tan42=1.3m*v2/m*v1, so v2/v1=0.69. The yellow car's initial velocity is 0.69 of that of the red car.
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lina2011 [118]

Answer:

1.) Frequency F = 890.9 Hz

2.) Wavelength (λ) = 0.893 m

Explanation:

1.) Given that the wavelength = 0.385m

The speed of sound = 343 m / s

To predict the frequency, let us use the formula V = F λ

Where (λ) = wavelength = 0.385m

343 = F × 0.385

F = 343/0.385

F = 890.9 Hz

2.) Given that the frequency = 384Hz

Using the formula again

V = F λ

λ = V/F

Wavelength (λ) = 343/384

Wavelength (λ) = 0.893 m

The two questions can be solved with the use of formula

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Answer:

3.51s

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Atomic nuclei are made of protons and neutrons. This fact by itself shows thatthere must be some other type of force in addition
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Which forces are shown on a free body diagram?
notsponge [240]

Answer:

What is a Free Body Diagram?

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5 0
2 years ago
A speed skater moving across frictionless ice at 9.2 m/s hits a 5.0 m wide patch of rough ice. She slows steadily, then continue
enot [183]

Answer:

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

Explanation:

The distance travelled on the rough ice is equal to the width of the rough ice.

distance d = 5.0 m

Initial speed u = 9.2 m/s

Final speed v = 5.8 m/s

The time taken to move through the rough ice can be calculated using the equation of motion;

d = 0.5(u+v)t

time t = 2d/(u+v)

Substituting the given values;

t = 2(5)/(9.2+5.8)

t = 2/3 = 0.66667 second

The acceleration is the change in velocity per unit time;

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a = (v-u)/t

Substituting the values;

a = (5.8-9.2)/0.66667

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a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

7 0
3 years ago
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