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grandymaker [24]
3 years ago
11

A red car of mass m is heading north (direction 0°). It collides at an intersection with a yellow car of mass 1.3m heading east

(direction 90°). Immediately after the collision, the cars lock together and travel at in direction 42°. What is the speed of the yellow car just before the collision?
Physics
1 answer:
Degger [83]3 years ago
6 0
After the collision, the momentum to the north comes completely from the red car, and the momentum to the east comes completely from the yellow car. Suppose the initial velocity of red car is v1, and yellow car is v2. The momentum of red car is v1*m, and yellow car is v2*1.3m. Since the cas travel in direction 42, we know that tan42=1.3m*v2/m*v1, so v2/v1=0.69. The yellow car's initial velocity is 0.69 of that of the red car.
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Answer:

(B) 0.06W

Explanation:

power absorbed by the resistor is given by \frac{V^2}{R}=I^2R

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p=\frac{12^2}{2.4\times 1000}=60mW =0.06W

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The distance in meters she would have moved before she begins to slow down is 11.25 m

<h3>LINEAR MOTION</h3>

A straight line movement is known as linear motion

Given that Ann is driving down a street at 15 m/s. Suddenly a child runs into the street. It takes Ann 0.75 seconds to react and apply the brakes.

To know how many meters will she have moved before she begins to slow down, we need to first list all the given parameters.

  • speed = 15 m/s
  • time t = 0.75 s

From definition of speed,

speed = distance / time

Make distance the subject of the formula

distance = speed x time

distance = 15 x 0.75

distance = 11.25m

Therefore, the distance in meters she would have moved before she begins to slow down is 11.25 m

Learn more about Linear motion here: brainly.com/question/13665920

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