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grandymaker [24]
3 years ago
11

A red car of mass m is heading north (direction 0°). It collides at an intersection with a yellow car of mass 1.3m heading east

(direction 90°). Immediately after the collision, the cars lock together and travel at in direction 42°. What is the speed of the yellow car just before the collision?
Physics
1 answer:
Degger [83]3 years ago
6 0
After the collision, the momentum to the north comes completely from the red car, and the momentum to the east comes completely from the yellow car. Suppose the initial velocity of red car is v1, and yellow car is v2. The momentum of red car is v1*m, and yellow car is v2*1.3m. Since the cas travel in direction 42, we know that tan42=1.3m*v2/m*v1, so v2/v1=0.69. The yellow car's initial velocity is 0.69 of that of the red car.
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Answer: 3 m/s

Explanation:

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The total momentum before the collision is given only by the cue ball, since the solid ball is initially at rest, therefore

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And the total momentum after the collision is given only by the solid ball, since the cue ball is now at rest, therefore:

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A 45.2-kg person is on a barrel ride at an amusement park. She stands on a platform with her back to the barrel wall. The 3.74-m
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Answer:

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Explanation:

<u>1. Name of the variables:</u>

   f:frequency\\\\ \omega:angular\text{ }speed\\\\ a_c:centripetal\text{ }acceleration\\\\ F_c:centripetal\text{ }force\\ \\ m:mass\\ \\ d:diameter\\ \\ r:radius\\ \\ g:gravitational\text{ }acceleration

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