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user100 [1]
3 years ago
13

A force of 100 N is applied to a crate at an angle of 60° to the horizontal surface. The force causes the crate to move 2 m acro

ss the floor. How much work is done on the crate?
Physics
2 answers:
vesna_86 [32]3 years ago
8 0

Answer:

100 J

Explanation:

The work done by the force on the crate is given by

W=Fd cos \theta

where

F = 100 N is the magnitude of the force

d = 2 m is the displacement of the crate

\theta=60^{\circ} is the angle between the direction of the force and the displacement

Substituting, we find

W=(100 N)(2 m)(cos 60^{\circ})=100 J

Aloiza [94]3 years ago
7 0
I just took it, got 100. its right. 
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The bellow of a territorial bull hippopotamus is measured at 100 dB above the threshold of hearing. What is the sound intensity?
Dmitriy789 [7]

Answer:

Explanation:

The hippopotamus hearing threshold is 100dB

β = 100 dB

The threshold of human hearing is Io = 1 × 10^-12 W/m²

The sound intensity level is given as

β = 10•Log(I / Io)

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Divided Both sides by 10

100 / 10 = Log(I / Io)

10 = Log(I / Io)

Take inverse Logarithm ( antilog) of both sides

10^10 = 10^[Log(I / Io)]

10^10 = I / Io

Then,

I = 10^10 × Io

I = 10^10 × 1 × 10^-12

I = 1 × 10^-2 W/m²

I = 0.01 W/m²

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Learn more about petroleum here brainly.com/question/21518946

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