Answer:
The magnitude of the force the garbage exerts on the floor of the service elevator is 12 N
Explanation:
Given;
mass of the garbage, m = 10.0 kg
acceleration of the elevator, a = 1.2 m/s²
The magnitude of the force the garbage exerts on the floor of the service elevator is given by;
F = ma
F = 10 x 1.2
F = 12 N
Therefore, the magnitude of the force the garbage exerts on the floor of the service elevator is 12 N
Answer:
Three (3).
Explanation:
The octet rule is a rule in chemistry that states that, chemical elements would either gain or loss electrons in their outermost shell in order to attain a stable electronic configuration i.e having eight (8) valence electrons in their outermost shell such as chemical elements found in group 8 (2-8-8) known as noble gas.
A phosphorus atom needs to gain three (3) electrons to achieve a full octet because the atomic number of phosphorus is 15 and as such it has the electronic configuration of 2-8-5 and needs three electron in order to become a stable element.
Answer:
2.9 kg
Explanation:
Given that a 0.775-m3 rigid tank initially contains air whose density is 1.18 kg/m3.
According to the definition of density
Density = mass/volume
1.18 = mass / 0.775
Mass = 1.18 × 0.775
Mass = 0.9145 kg
Given that the tank is connected to a high-pressure supply line through a valve. The valve is opened, and air is allowed to enter the tank until the density in the tank rises to 4.95 kg/m3.
Using the same density formula
Density = mass/volume
4.95 = mass / 0.775
mass = 3.83625 kg
To determine the mass of air that has entered the tank, take away the mass of the air initial in the tank from the mass calculated
Mass = 3.83625 - 0.9145
Mass = 2.923kg
Therefore, the mass of air that has entered the tank is 2.9 kg approximately.
Answer:
MY friend has already described the purpose of projectile motion so I will quickly go through the uses of each equation ...
Explanation:
TIME OF FLIGHT = it is given as 2Usin tita/g...it is the total time taken to and fro...it is 2x of the time taken ....
TIME taken ..t= Usin tita / g.....is the time taken to reach the maximum height which is 1/2 the TOTALTIME OF FLIGHT GIVEN ABOVE ..
MAXIMUM HEIGHT: the maximum height is the height attained by the projectile when projected ...it is calculate using the formula = U^2 sin^2 tita / 2g
Range =Search Results
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An object launched into projectile motion will have an initial launch angle anywhere from 0 to 90 degrees. The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 sin 2 θ i g .
