How fast is the runner moving between 2-3 seconds? Is the other question please help

Physics

1 answer:

Rainbow [258]3 years ago

4 0

Answer:

Concept: Physics analysis

We have a distance vs time graph
That indicates that we are analyzing the distance traveled by either a person or a particle
The runner starts at 4 meters and over the interval of a second runs to 12 meters reaching the 16 meter mark. The runner stood at 16 meter mark for one full second and then runs back 10 meter over the course of one second reaching 6 meter. The runner runs forward again for a second traveling 6 meters, ending at the 12 meter mark.

You might be interested in

How is the Un-DSM different from the DSM-IV-TR?

Ede4ka [16]

Answer:

In the DSM-IV, patients only needed one symptom present to be diagnosed with substance abuse, while the DSM-5 requires two or more symptoms in order to be diagnosed with substance use disorder. The DSM-5 eliminated the physiological subtype and the diagnosis of polysubstance dependence.

Explanation:

hope this help you

4 0

3 years ago

A 1.0-m-long copper wire of diameter 0.10 cm carries a current of 50.0 A to the east. Suppose we apply to this wire a magnetic f

Lostsunrise [7]

Answer:

1.379 x $10^{-3}$ T. and into the page.

Explanation:

Download pdf

3 0

3 years ago

A construction crane's cable lifts a 49.5-kg box upward with an acceleration of 1.30 m/s2. Find the tension in the rope.

Basile [38]

Verrrrry interesting question !

Force= (mass) x (acceleration)

 (49.5kg) x (1.3 m/s²) =

  Net force on the box is 64.25 newtons upward.

That's the net force. It's the combination of the tension in the rope
pulling the box up, and the force of gravity pulling the box down.

Force of gravity = "weight" = (mass) x (gravity) =

 (49.5) x (9.8) = 485.1 newtons downward

The tension in the rope must be enough to balance the downward force
of gravity PLUS provide another 64.25 newtons upward.

 Tension = (485.1) + (64.25) = 549.35 newtons

6 0

3 years ago

A father and his young son get on a teeter-totter. The son sits 2 m fromthe center, but the father has to sit closer to balance.

Luda [366]

Answer:

The distance of the father from the center is $d_f = \frac{1}{2} \ m$

Explanation:

From the question we are told that

The distance of the son from the center is $d_s = 2 \ m$

Let the mass of the son be $m_s$

then the mass of the father is $m_f = 4m_s$

Now for the teeter-totter to be balanced the torque due to the weight of the father must be equal to the torque due to the weight the son, this is mathematically represented as

$\tau_s = \tau_f$