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tester [92]
2 years ago
15

Which part of the scientific method is most likely to lead to changes in a theory? (1 point)

Physics
1 answer:
Ksenya-84 [330]2 years ago
6 0

Answer:

results

Explanation:

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It is known that birds can detect the earth's magnetic field, but the mechanism of how they do this is not known. It has been su
san4es73 [151]

Answer:

EMF = 5.01 \times 10^{-4} Volts

Explanation:

Here we know that the EMF induced in this Field is given as

EMF = vBL

here B = perpendicular component of magnetic field

v = speed of the bird

L = length of the wings

now we have

B = 5\times 10^{-5} sin40

v = 13 m/s

L = 1.2 m

now we have

EMF = (13)(3.21 \times 10^{-5})(1.2)

EMF = 5.01 \times 10^{-4} Volts

8 0
3 years ago
What are the advantages of using the metric system? SELECT ALL THAT APPLY
alexandr402 [8]

D. used by the entire scientific community

B.  more accurate system of measurement

3 0
2 years ago
A boat is towing two skiers at the same time. how long should the tow lines be?
BigorU [14]
The tow lines for the two skiers must be of the same length. No matter the number of skiers towed, the length of the tow lines must be the same. Towing people on ski requires additional skills and some safety precautions must be taken. Most importantly, it is dangerous and illegal to tow at night. 
4 0
3 years ago
Fish are able to acquire the oxygen needed for respiration under water using gills. This is an example of which type of adaptati
stiks02 [169]

Answer:

Structural

Explanation:

Structural adaptations are a change to a organism's body, gills are part of the fish's body which would be why this is a structural adaptation!

Hope this helped! Stay safe have a good day or night!

3 0
3 years ago
A track is traveling a. a speed of 25.0 m/s along a level road. A crate is resting on the bed of the truck, and the coefficient
Mice21 [21]

To solve this problem it is necessary to apply the concepts related to

conservation of energy, for this case manifested through work and kinetic energy.

W = \Delta KE

W = F*d

Where,

F= Force (Frictional at this case F_r = \mu N)

d= Distance

\Delta KE = \frac{1}{2} mv^2

Where,

m = mass

v = velocity

Equation both terms,

F*d = \frac{1}{2}mv^2

\mu mg *d = \frac{1}{2}mv^2

\mu g * d = \frac{1}{2}v^2

d = \frac{1}{2} \frac{v^2}{\mu g}

Replacing with our values we have that

d = \frac{1}{2} \frac{25^2}{0.65*9.8}

d = 49.05m

Therefore the shortest distance in which the truck can come to a halt without causing the crate to slip forward relative to the truck is 49.05m

6 0
3 years ago
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