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Nataliya [291]
3 years ago
10

PLEASE HELP! (Needs to be graphed)

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
3 0

Answer:

answer is 25

Step-by-step explanation:

25 times 4

Sonbull [250]3 years ago
3 0

Answer:

Step-by-step explanation:

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What is the volume of a ball that has a diameter of 9 inches? Round to the nearest whole number
nalin [4]
Ball=sphere
Vsphere=pir^3
d/2=r
d=9
9/2=4.5=r
V=pi4.5^3
V=pi91.125
aprox pi=3.141592
V=286.227
round
V=286 in^3
4 0
3 years ago
A school is arranging a field trip to the zoo. The school spends 635.85 dollars on passes for 43 students and 2 teachers. The sc
aalyn [17]

Answer:

$22.67

Step-by-step explanation:

The school spends 635.85 dollars on passes for 43 students and 2 teachers, then the school spends

\$635.85 :(43+2)=\$14.13 per person.

The school also spends 367.22 dollars on lunch for just the students, so the school spends

\$367.22 :43=\$8.54 per person.

In total, a pass and lunch for each student was spent

\$14.13+\$8.54=\$22.67

7 0
3 years ago
Prove A-(BnC) = (A-B)U(A-C), explain with an example​
NikAS [45]

Answer:

Prove set equality by showing that for any element x, x \in (A \backslash (B \cap C)) if and only if x \in ((A \backslash B) \cup (A \backslash C)).

Example:

A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace.

B = \lbrace0,\, 1 \rbrace.

C = \lbrace0,\, 2 \rbrace.

\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}.

\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}.

Step-by-step explanation:

Proof for [x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))] for any element x:

Assume that x \in (A \backslash (B \cap C)). Thus, x \in A and x \not \in (B \cap C).

Since x \not \in (B \cap C), either x \not \in B or x \not \in C (or both.)

  • If x \not \in B, then combined with x \in A, x \in (A \backslash B).
  • Similarly, if x \not \in C, then combined with x \in A, x \in (A \backslash C).

Thus, either x \in (A \backslash B) or x \in (A \backslash C) (or both.)

Therefore, x \in ((A \backslash B) \cup (A \backslash C)) as required.

Proof for [x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]:

Assume that x \in ((A \backslash B) \cup (A \backslash C)). Thus, either x \in (A \backslash B) or x \in (A \backslash C) (or both.)

  • If x \in (A \backslash B), then x \in A and x \not \in B. Notice that (x \not \in B) \implies (x \not \in (B \cap C)) since the contrapositive of that statement, (x \in (B \cap C)) \implies (x \in B), is true. Therefore, x \not \in (B \cap C) and thus x \in A \backslash (B \cap C).
  • Otherwise, if x \in A \backslash C, then x \in A and x \not \in C. Similarly, x \not \in C \! implies x \not \in (B \cap C). Therefore, x \in A \backslash (B \cap C).

Either way, x \in A \backslash (B \cap C).

Therefore, x \in ((A \backslash B) \cup (A \backslash C)) implies x \in A \backslash (B \cap C), as required.

8 0
2 years ago
A box contains 6 red marbles, 4 green marbles, 3 blue marbles, and 2 yellow marbles. If one marble is chosen at random, what is
blondinia [14]

Answer:

0.2

Step-by-step explanation:

6+4+3+2=total no of marble

=15

no of blue marble 3

\frac{3}{15}  \\  =  \frac{1}{5 }  \\  = 0.2

3 0
3 years ago
Using this formula, calculate the value of the z-statistic. Round your answer to the tenths place.
Nitella [24]

Answer:

z= -2.5

Step-by-step explanation:

7 0
3 years ago
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