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3 years ago

Is this equation completely balanced? 2C8H8 + 25O2 8CO2 + 18H2O

Chemistry

2 answers:

lianna [129]3 years ago

4 0

Answer: Option (A) is the correct answer.

Explanation:

For an equation to be completely balanced, there should be equal number of reactants and products.

In the given equation.

$2C_{8}H_{8} + 25O_{2}\rightarrow 8CO_{2} + 18H_{2}O$

Number of carbon atoms on reactant side = 16

Number of hydrogen atoms on reactant side = 16

Number of oxygen atoms on reactant side = 50

Number of carbon atoms on product side = 8

Number of hydrogen atoms on product side = 36

Number of oxygen atoms on product side = 34

Hence, we can conclude that total number of reactants does not equal total number of products therefore, this equation is not completely balanced.

goblinko [34]3 years ago

3 0

<span>A.No, because the number of carbon, hydrogen & oxygen atoms on both sides of the equation are not equal</span>

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Consider the reaction 2N2(g) O2(g)2N2O(g) Using the standard thermodynamic data in the tables linked above, calculate Grxn for t

ratelena [41]

Answer:

$\Delta G^0 _{rxn} = 207.6\ kJ/mol$

ΔG ≅ 199.91 kJ

Explanation:

Consider the reaction:

$2N_{2(g)} + O_{2(g)} \to 2N_2O_{(g)}$

temperature = 298.15K

pressure = 22.20 mmHg

From, The standard Thermodynamic Tables; the following data were obtained

$\Delta G_f^0 \ \ \ N_2O_{(g)} = 103 .8 \ kJ/mol$

$\Delta G_f^0 \ \ \ N_2{(g)} =0 \ kJ/mol$

$\Delta G_f^0 \ \ \ O_2{(g)} =0 \ kJ/mol$

$\Delta G^0 _{rxn} = 2 \times \Delta G_f^0 \ N_2O_{(g)} - ( 2 \times \Delta G_f^0 \ N_2{(g)} + \Delta G_f^0 \ O_{2(g)})$

$\Delta G^0 _{rxn} = 2 \times 103.8 \ kJ/mol - ( 2 \times 0 + 0)$

$\Delta G^0 _{rxn} = 207.6\ kJ/mol$

The equilibrium constant determined from the partial pressure denoted as $K_p$ can be expressed as :

$K_p = \dfrac{(22.20)^2}{(22.20)^2 \times (22.20)}$

$K_p = \dfrac{1}{ (22.20)}$

$K_p$ = 0.045

$\Delta G = \Delta G^0 _{rxn} + RT \ lnK$

where;

R = gas constant = 8.314 × 10⁻³ kJ

$\Delta G =207.6 + 8.314 \times 10 ^{-3} \times 298.15 \ ln(0.045)$

$\Delta G =207.6 + 2.4788191 \times \ ln(0.045)$

$\Delta G =207.6+ (-7.687048037)$

$\Delta G =$ 199.912952 kJ

ΔG ≅ 199.91 kJ

7 0

4 years ago

A cube of ice melts in a beaker to form 10 g of water. What is the best estimate of the mass of the ice cube?

prohojiy [21]

I think the answer is 10g
when you freeze a specific amount of water into an ice cube, only the form and the density is changed, while the mass will be pretty much the same.
Probably the mass of the melted water will be a little bit less than the cube (if count the mass that released to the air) , but the amount will NOT BE SIGNIFICANT.

6 0

3 years ago

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80.0 liters of oxygen gas is collected over water at 50 degrees celcius. the atomsphereic pressure in the room is 96.00 kPA. wha

Drupady [299]

Partial pressure O2 = total pressure - vapour pressure H2O at 50 deg C
Vapour pressure H2O at 50 deg C = 12.332 kPa
= 96.00 kPa - 12.332 kPa = 83.67 kPa

3 0

3 years ago

How do you balance this chemical equation?

ryzh [129]

Ba(ClO3)2 --> BaCl2 + 3 O2

The fact that there are some ionic compounds doesn't matter. Just use the formulas.
barium chlorate = Ba(ClO3)2
barium chloride = BaCl2
Oxygen = O2

Now create the unbalanced equation
Ba(ClO3)2 --> BaCl2 + O2

And balance in the usual fashion. Count the atoms of each element on both sides
Ba = 1, 1
Cl = 2, 2
O = 6, 2

And oxygen is out of balance. But can be easily handled with a 3 coefficient on the right hand side. So:
Ba(ClO3)2 --> BaCl2 + 3 O2

And we have a balanced equation.

6 0

4 years ago

How many grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl? Show all of the work needed to solve this

vovikov84 [41]

V=4.8 L
c=5.0 mol/L
M(Mg)=24.3 g/mol

1) n(HCl)=cv

2) m(Mg)=M(Mg)n(HCl)/2

3) m(Mg)=M(Mg)cv/2
m(Mg)=24.3*5*4.8/2=291.6 g

7 0

3 years ago

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