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2 years ago

NOOOO LINNKKKSSS RIGHT ANSWERS ONLY!!!!!!

Chemistry

2 answers:

lawyer [7]2 years ago

3 0

I belive its D if not right sorry.

Evgesh-ka [11]2 years ago

3 0

I believe the answer should be C

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How many places are there electrons in the innermost shell of an atom

Sergio [31]

There are two places for electrons in the inner most shell

5 0

3 years ago

Suppose a gas starts with a volume of 4.52L, temperature of 23 C, and pressure of 102,00 Pa. If the volume changes to 4.83L and

ivanzaharov [21]

Answer:

The answer to your question is P2 = 84.16 kPa

Explanation:

Data

Volume 1 = V1 = 4.52 L Volume 2 = V2 = 4.83 l

Pressure 1 = P1 = 102 kPa Pressure 2 = P2 = ?

Temperature 1 = T1 = 23°C Temperature 2 = T2 = -12°C

Process

1.- Convert the temperature to °K

Temperature 1 = 23 + 273 = 296°K

Temperature 2 = -12 + 273 = 261°K

2.- Use the Combined Gas law to solve this problem

P1V1/T1 = P2V2/T2

-Solve for P2

P2 = P1V1T2 / T1V2

-Substitution

P2 = (102)(4.52)(261) / (296)(4.83)

-Simplification

P2 = 120331.44 / 1429.68

-Result

P2 = 84.16 kPa

8 0

3 years ago

Nitrogen gas is being withdrawn at the rate of 4.5 g/s from a 0.15-m3 cylinder, initially containing the gas at a pressure of 10

faust18 [17]

Answer:

Final temperature = 152.57K,

Pressure = 0.6907 bar.

dT/dt = - 1,151 K/s.

Explanation:

The first thing to do here is to write out the equation for mass balance as given below:

dN/dt = N -------------------------------------------------------------------------------------------(1).

N = P/T, then, substitute the values given in the question into:

d[p/T]/ dt = [- 4.5/28 × 8.314]/0.15 = - 8.9 × 10⁻⁵ bar/K.s.

Thus, there is the need to integrate, Integrate [p/T]f = 10/320 - 8.9 × 10⁻⁵ bar/K.s. ------------------------------------(2).

NB; fT = final temperature, fP = final pressure and iT = initial temperature.

Also, [ fT]³⁰/₈.₃₁₄/ [fP] = [iT]³⁰/₈.₃₁₄/ Pi] = [ 320]³⁰/₈.₃₁₄/ 10.

Therefore, [fT]³⁰/₈.₃₁₄ = 109.52 × 10⁶.

Final temperature= [fP]³⁰/₈.₃₁₄ × 169.05.

Note that fP/ [fP]³⁰/₈.₃₁₄ × 169.05 = 10/320 - 8.9 × 10⁻⁵.

Therefore, [fP]¹ ⁻ ³⁰/₈.₃₁₄ = 0.7651.

Hence, Final temperature = 152.57K,

Pressure = 0.6907 bar

dT/ dt = N[RT]² / Cv . PV.

R = 30 - 8.314 = 21.86 J/mol K.

Then, the rate of change of the gas temperature at this time = dT/dt = - 1,151 K/s.

4 0

2 years ago

the half-life of chromium 51 is 28 days if the sample contained 510 grams how much chromium would remain after 86 days

Anni [7]

Answer: 3.285714285714286 I believe this is what it is

Explanation:

You have to divide 50 by 28 then times it by 510 then divide by 86

5 0

3 years ago

The initial pressure of a mixture of C6H6 and an excess of H2 in a rigid vessel is 1.21 atm. A catalyst is introduced. After the

KengaRu [80]

Answer:

mole fraction of C6H6 = 0.613 atm

Explanation:

The equation for this reaction is :

$C_6H_6 _{(g)} + 3H_2_{(g)} \to C_6H_{12}_{(g)}$

Initial P₁ P₂ 0

Final 0 P₂ -P₁/2 P₁

After completion of the reaction;

P₁ + P₂ = 1.21 atm ----- (1)

P₂ - P₁/2 + P₁ = 0.839 atm

P₂ + P₁/2 = 0.839 atm ----- (2)

Subtracting (2) from (1); we have:

P₁/2 = 0.371

P₁ = 0.742 atm

From(1)

P₁ + P₂ = 1.21 atm

0.742 atm + P₂ = 1.21 atm

P₂ = 1.21 atm - 0.742 atm

P₂ = 0.468 atm

Thus, the partial pressure of C6H6 = 0.742 atm

∴

Partial pressure = Total pressure × mole fraction of C6H6

mole fraction of C6H6 = Partial pressure / Total pressure

mole fraction of C6H6 = 0.742 atm / 1.21 atm

mole fraction of C6H6 = 0.613 atm

5 0

3 years ago