Answer:
10 Litre
Explanation:
Given that ::
v1 = 25L ; n1 = 1.5 mole ; v2 =? ; n2 = (1.5-0.9) = 0.6 mole
Using the relation :
(n2 * v1) / n1 = (n2 * v2) / n2
v2 = (n2 * v1) / n1
v2 = (0.6 mole * 25 Litre) / 1.5 mole
v2 = 15 / 1.5 litre
v2 = 10 Litre
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If the question includes x only than it’s value would be 1
Answer:
t = 37.1 s
Explanation:
The equation for the reaction is given as;
2 N2O5(g) --> 4 NO2 + O2
Initial: 0.110 - -
change: -2x +4x +x
Final: 0.110 - 2x +4x +x
But final = 0.150atm;
0.110 - 2x + 4x + x = 0.150 atm
3x = 0.150 - 0.110
x = 0.0133 atm
Pressure in reactant side;
0.110 - 2x
0.110 - 2 (0.0133) = 0.0834 atm
The integral rate law expression is given as;
ln ( [A] / [Ao] ) = -kt
k = rate constant = 7.48*10^-3*s-1
ln (0.0834/0.11) = (7.48*10^-3) t
upon solving, t = 37.1 s