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3 years ago

Write the equation for the decay of kr-85

Chemistry

2 answers:

iris [78.8K]3 years ago

8 0

Answer:see image attached

Explanation:

Kr-85 turns spontaneously into a Rubidium nucleus by emitting a beta particle and a gamma ray. The rubidium nucleus has the same mass as the krypton nucleus. The gamma rays carries off the excess energy released. It is actually a photon of light. A beta particle is actually an electron. A lot of energy is usually released in this process.

Ray Of Light [21]3 years ago

7 0

<u>Answer</u>:-

Kr-85 changes into Rb-86 by mostly beta decay.

Equation:

85Kr → Rb-86 + β-particle + Energy

Explanation:

1)Link:

http://www.nucleide.org/DDEP_WG/Nuclides/Kr-85_tables.pdf

2) Photo

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2 years ago

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3 years ago

When a certain amount of MgF2 is added to water, the freezing point lowers by 3.5° C. What was the molality of the

Leni [432]

The molality of the solution is obtained as 0.63 m.

<h3>What is the freezing point?</h3>

The freezing point is the temperature at which the liquid is converted into solid.

We know that;

ΔT = 3.5° C

K = 1.86° C/m

i = 3

m = ?

Thus;

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2 years ago

A chemist must dilute of aqueous aluminum chloride solution until the concentration falls to . He'll do this by adding distilled

marshall27 [118]

Answer:

0.257 L

Explanation:

The values missing in the question has been assumed with common sense so that the concept could be applied

Initial volume of the AICI3 solution $=23.1 \mathrm{mL}$

Initial Molarity of the solution $=833 \mathrm{mM}$

Final molarity of the solution $=75.0 \mathrm{mM}$

Final volume of the solution $=?$

From Law of Dilution, $M_{f} V_{f}=M_{i} V_{i}$

$\Rightarrow V_{f}=\frac{M_{i} V_{i}}{M_{f}}=\frac{833 \mathrm{mM} \times 23.1 \mathrm{mL}}{75.0 \mathrm{mM}}=256.564 \mathrm{mL}=0.256564 \mathrm{L}=0.257 L$

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3 years ago

What is the pH of a 8.7 x 10^-12 M OH- solution ? pH= ?

vivado [14]

PH=14-pOH

pOH=-lg[OH⁻]

pH=14+lg[OH⁻]

pH=14+lg(8.7*10⁻¹²)=14-11.06=2,94

5 0

3 years ago

Read 2 more answers