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andriy [413]
3 years ago
8

In the redox reaction below, which is the reducing agent? Cl- Cl2 Mn2+ MnO2

Chemistry
1 answer:
bearhunter [10]3 years ago
4 0

Answer:

            Cl⁻ is the reducing agent.

Explanation:

The redox reaction is as follow:

                    MnO₂  + 4H⁺ + 2Cl⁻   →   Mn²⁺ + 2H₂O + Cl₂

One should know the following terms,

Reducing agent:

                          An atom or element which tends to lose electron during a chemical reaction and get itself oxidized. In above reaction Cl⁻ is reducing agent as it carries a negative charge (means it has one extra electron) on the reactant side while, it has zero oxidation state on the product side. It means going from -1 to 0 the Cl lost one electron hence, it is an reducing agent according to definition.

Oxidizing Agent:

On the other hand oxidizing agent is an element or compound which tends to accepts electron(s) and get itself reduced. In above reaction Mn has an oxidation state of +4 on reactant side and after gaining electron from Cl it has changed to +2 on the product side. Hence, it has reduced but has oxidized the Cl atom so it is an oxidizing agent according to definition.

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The symbol for the hydronium ion is H3O+.
An hydronium ion is usually formed when an acid is present in water. The hydronium ion is made up of three atoms of hydrogen and one atom of oxygen, thus an hydronium ion is a water molecule which has gained an extra positive hydrogen ion. 
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How many molecules are there in 5H20?
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Answer:

The number before any molecular formula applies to the entire formula. So here you have five molecules of water with two hydrogen atoms and one oxygen atom per molecule. Thus you have ten hydrogen atoms and five oxygen atoms in total.

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The heat released by one mole of sugar from a bomb calorimeter experiment is 5648 kJ/mol. The balanced chemical reaction equatio
Bogdan [553]

Answer:

The answer to your question is the letter C) 5648 kJ/mol

Explanation:

Data

                C₁₂H₂₂O₁₁  +  12 O₂  ⇒   12 CO₂  +  11 H₂O

H° C₁₂H₂₂O₁₁ = -2221.8 kJ/mol

H° O₂ = 0 kJ / mol

H° CO₂ = -393.5 kJ/mol

H° H₂O = -285.8 kJ/mol

Formula

ΔH° = ∑H° products - ∑H° reactants

Substitution

ΔH° = 12(-393.5) + 11(-285.8) - (-2221.8) - (0)

ΔH° = -4722 - 3143.8 + 2221.8

Result

ΔH° = -5644 kJ/mol

6 0
3 years ago
Hotosynthesis can be represented by 6CO2(g)+6H2O(l)⇌C6H12O6(s)+6O2(g) Which of the following will be false when the photosynthes
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Answer: Option (b) and (d) are correct.

Explanation:

An equilibrium reaction is defined as the reaction in which rate of forward reaction equals rate of backward reaction.

A photosynthesis reaction is the reaction in which plants in the presence of sunlight, water, and carbon dioxide make their own food.  

  • The amount of carbon dioxide consumed will be equal to the rate of formation of oxygen into the atmosphere.

Hence, the statement rate of formation of O_{2} is equal to the rate of formation of CO_{2} is true.

  • Concentration of oxygen may remain constant but it will not decrease. Hence, the statement concentration of O_{2} will begin decreasing, is false.
  • As both oxygen and carbon dioxide are present in an equilibrium reaction, So, their concentration will not change.

        Hence, the statement concentrations of CO_{2} and O_{2} will not change, is true.

  • Concentration of carbon dioxide and oxygen will also depend on the limiting reagent. So, it is not necessary that the concentrations of CO_{2} and O_{2} will be equal.

Some amount of carbon dioxide might escape out into the air.

Hence, the statement concentrations of CO_{2} and O_{2} will be equal, is false.

3 0
4 years ago
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