The nucleus of an atom consists of:

use the particle theory to explain why hot chocolate powder dissolves more rapidly in hot water than cold water

snow_lady [41]

Answer:

2) To dissolve, solvent particles must come in contact with solvent particles. Particles of hot water are moving much more rapidly than particles of cold water. Hence, in hot water more water particles will come in contact with hot chocolate powder than in cold water, resulting in faster dissolving.

Explanation:

6 0

3 years ago

What does the term electrically neutral mean when discussing ionic compounds?

viva [34]

If you look at ionic compound, they are formed by a metal and a nonmetal. A metal is a positive ion after losing electron(s) and a nonmetal is a negative ion after gaining electron(s). Since there are both + and -, they are now electrically neutral.

6 0

3 years ago

The two common chlorides of phosphorus, PCl3, and PCl5, both important for the production of the other phosphorus compounds, coe

Irina18 [472]

Answer:

For a: The value of $K_c$ for the given reaction is 271.6

For b: The value of $K_p$ for the reaction is 6.32

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For $PCl_5$ :

Given mass of $PCl_5$ = 0.105 g

Molar mass of $PCl_5$ = 208.24 g/mol

Putting values in equation 1, we get:

$\text{Moles of }PCl_5=\frac{0.105g}{208.24g/mol}=5.04\times 10^{-4}mol$

For $PCl_3$ :

Given mass of $PCl_3$ = 0.220 g

Molar mass of $PCl_5$ = 137.33 g/mol

Putting values in equation 1, we get:

$\text{Moles of }PCl_3=\frac{0.220g}{137.33g/mol}=1.60\times 10^{-3}mol$

For $Cl_2$ :

Given mass of $Cl_2$ = 2.12 g

Molar mass of $Cl_2$ = 71.0 g/mol

Putting values in equation 1, we get:

$\text{Moles of }Cl_2=\frac{2.12g}{71.0g/mol}=0.029mol$

Volume of the flask = 25.0 L

For the given chemical equation:

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

For a:

The equation used to calculate concentration of a solution is:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}$

The expression of $K_c$ for above reaction follows:

$K_c=\frac{PCl_5}{PCl_3\times Cl_2}$

We are given:

$[PCl_5]=\frac{5.04\times 10^{-4}mol}{25L}$

$[PCl_3]=\frac{1.60\times 10^{-3}mol}{25L}$

$[Cl_2]=\frac{0.029mol}{25L}$

Putting values in above equation, we get:

$K_c=\frac{(\frac{5.04\times 10^{-4}}{25})}{(\frac{1.60\times 10^{-3}}{25})\times (\frac{0.029}{25})}\\\\K_c=271.6$

Hence, the value of $K_c$ for the given reaction is 271.6

For b:

Relation of $K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

where,

$K_p$ = equilibrium constant in terms of partial pressure = ?

$K_c$ = equilibrium constant in terms of concentration = 271.6

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = $250^oC=250+273=523K$

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=1-2=-1$

Putting values in above equation, we get:

$K_p=271.6\times (0.0821\times 523)^{-1}\\\\K_p=6.32$

Hence, the value of $K_p$ for the reaction is 6.32

7 0

4 years ago

James exclaims to his chemistry teacher that a new element has been discovered that fits between Nickel and Copper on the period

myrzilka [38]

Aye you have the same class as me bruh I need help on some chemistry qustions

8 0

3 years ago

Read 2 more answers

Calculate the number of grams of deuterium in an 80,000-L swimming pool, given deuterium is 0.0150% of natural hydrogen

fiasKO [112]

Answer:

$m_{Deu}=2666.7g$

Explanation:

Hello,

In this case, we can apply the following mole-mass-density relationship in order to compute the required grams of deuterium, considering that it is the 0.0150% (molar basis) of natural hydrogen (H₂):

$m_{Deu}=80000LH_2O*\frac{1000gH_2O}{1LH_2O}*\frac{1molH_2O}{18gH_2O} *\frac{1molH_2}{1molH_2O} *\frac{2gH_2}{1molH_2} *\frac{2*0.0150g\ Deu}{100gH_2} \\\\m_{Deu}=2666.7g$

Best regards.

4 0

3 years ago