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andreyandreev [35.5K]
3 years ago
13

An airplane is flying at an elevation of 3,750 feet and lands on an airstrip 250 below sea level. What is the difference between

these two elevations?
Mathematics
2 answers:
Anit [1.1K]3 years ago
5 0

Answer:

Answer:

4000 feet

Step-by-step explanation:

because *meme image* MATH IS MATH

stiv31 [10]3 years ago
3 0

Answer:

4000 feet

Step-by-step explanation:

GIVEN: An airplane is flying at an elevation of 3,750\text{ feet} and lands on an airstrip 250\text{ feet} below sea level.

TO FIND: What is the difference between these two elevation.

SOLUTION:

Elevation of airplane while flying =3750\text{ feet}

As airstrip is below sea level,

Elevation airplane while on airstrip =-250\text{ feet}

Difference between elevations =\text{elevation when flying}-\text{elevations while on airstrip}

=3750-(-250)

=3750+250 \text{feet}

=4000\text{ feet}

Hence difference between elevations is 4000 feet.

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Answer:

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Step-by-step explanation:

Following dates are given

On November 10 = Merchandise ordered

Date of an invoice prepared, dated and mailed = November 13

Date when the merchandised received by the buyer = November 18

So, the credit period begins when the invoice is prepared, dated and the mailed by the seller to the buyer as it is the evidence of that the merchandise is ordered            

4 0
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The graph of a non-invertible function passes through the points (- 1, 2), (0, 6) and (3, - 4) How is the inverse of this functi
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Answer:

The order of ordered pairs of a function and its inverse reverse. The graph of the inverse of this function passes through the points (2,-1), (6,0), (-4,3).

Explanation:

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This table represents Jennifer's check register. Her checking account had a balance of $2,322.75 on April 24.
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Answer:

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6 0
2 years ago
1. In an auditorium, there are 21 seats in the first row and 26 seats in the second row. The number of seats in a row continues
kondor19780726 [428]
1. Let s_n be the number of seats in the n-th row. The number seats in the n-th row relative to the number of seats in the (n-1)-th row is given by the recursive rule

s_n=s_{n-1}+5


Since s_1=21, we have

s_2=s_1+5
s_3=s_2+5=s_1+2\cdot5
s_4=s_3+5=s_1+3\cdot5
\cdots
s_n=s_{n-1}+5=\cdots=s_1+(n-1)\cdot5

So the explicit rule for the sequence s_n is

s_n=21+5(n-1)\implies s_n=5n+16

In the 15th row, the number of seats is


s_{15}=5(15)+16=91

2. Let p_n be the amount of profit in the n-th year. If the profits increase by 6% each year, we would have

p_2=p_1+0.06p_1=1.06p_1
p_3=1.06p_2=1.06^2p_1
p_4=1.06p_3=1.06^3p_1
\cdots
p_n=1.06p_{n-1}=\cdots=1.06^{n-1}p_1

with p_1=40,000.

The second part of the question is somewhat vague - are we supposed to find the profits in the 20th year alone? the total profits in the first 20 years? I'll assume the first case, in which we would have a profit of


p_{20}=1.06^{19}\cdot40,000\approx121,024

3. Now let p_n denote the number of pushups done in the n-th week. Since 3\cdot4=12, 12\cdot4=48, and 48\cdot4=192, it looks like we can expect the number of pushups to quadruple per week. So,

p_n=4p_{n-1}

starting with p_1=3.

We can apply the same reason as in (2) to find the explicit rule for the sequence, which you'd find to be

p_n=4^{n-1}p_1\implies p_n=4^{n-1}\cdot3
6 0
3 years ago
?
ExtremeBDS [4]

Answer:

C) Area of Triangle is 102 Square Units

3 0
3 years ago
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